Answer:
a
=
7
b
=
−
5
/2
Let's solve your system by substitution.
5a+4b=25 and 3a−8b=41
Rewrite equations:
5a+4b=25;3a−8b=41
Step: Solve5a+4b=25for a:
5a+4b=25
5a+4b+−4b=25+−4b(Add -4b to both sides)
5a=−4b+25
5a =
−4b+25
5
a/5 = −4b+25
/5
(Divide both sides by 5)
a=
−4
/5
b +5
Step: Substitute
−4
/5
b+5 for a in 3a−8b=41:
3a−8b=41
3(
−4
/5
b+5)−8b=41
−52
/5
b+15=41 (Simplify both sides of the equation)
−52
/5
b+15+−15=41+−15 (Add -15 to both sides)
−52
/5
b=26
−52
/5
b
/−52
/5
= 26
/−52
/5
(Divide both sides by (-52)/5)
b=
−5
/2
Step: Substitute −5
/2 for b in a=
−4
/5
b+5:
a=
−4
/5
b+5
a=
−4
/5
(
−5/
2
)+5
a=7 (Simplify both sides of the equation)
