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3 years ago

Find the distance between the 2 points (6, - 4) and (2, - 7). Please show me how you found it.

1 answer:

5 0

$\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ 6}}\quad ,&{{ -4}})\quad 
% (c,d)
&({{ 2}}\quad ,&{{ -7}})
\end{array}\qquad 
% distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
d=\sqrt{[2-6]^2+[-7-(-4)]^2}\implies d=\sqrt{(2-6)^2+(-7+4)^2}$

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Write an algebraic expression for the situation. 7 less than the quotient of y divided by 4

melomori [17]

Answer:

7- (y/4)

Step-by-step explanation:

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2 years ago

Read 2 more answers

PLs help

Pavel [41]

A) The hypotenuse is the longest side of the triangle .In the figure EG is the hypotenuse.The given angle is <G=40 degrees.The side adjacent is FG= 10 units.

The question is asking us to find the trigonometry ratio which will help us find EG.We can use cos as cos is ratio of adjacent and hypotenuse.

$cos 40=\frac{10}{Hypotenuse EG.}$

B) Cos 40 =0.766.

Substituting tan40 value we have:

$0.766=\frac{10}{EG}$

EG=13.05.

C)Sum of angles in triangle is 180.

<E+<F+<G=180

<E+90+40=180

<E+130=180

<E=50 degrees.

D) $Tan 40=\frac{EF}{10}$

EF=8.39

E) Area of triangle EFG= $\frac{1}{2}x base x height.$

A rea of the triangle = $\frac{1}{2}x8.39x13.05$

Area= 54.75 square units.

5 0

3 years ago

Write the slope intercept form of the equation.

Elza [17]

Hello!

The slope intercept form equation is shown below.

y=mx+b

In this equation, m represents the slope and b is the y-intercept.

We can just plug in our numbers to find our answer.

y=3x-2

I hope this helps!

4 0

3 years ago

The time between arrivals of customers at the drive-up window of a bank follows an exponential probability distribution with a m

castortr0y [4]

Answer:

a) 50.34% probability that the arrival time between customers will be 7 minutes or less.

b) 24.42% probability that the arrival time between customers will be between 3 and 7 minutes

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \mu e^{-\mu x}$

In which $\mu = \frac{1}{m}$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\mu x}$

The probability of finding a value higher than x is:

$P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}$

Mean of 10 minutes:

This means that $m = 10, \mu = \frac{1}{10} = 0.1$

A. What is the probability that the arrival time between customers will be 7 minutes or less?

$P(X \leq x) = 1 - e^{-\mu x}$

$P(X \leq 7) = 1 - e^{-0.1*7} = 0.5034$

50.34% probability that the arrival time between customers will be 7 minutes or less.

B. What is the probability that the arrival time between customers will be between 3 and 7 minutes?

$P(3 \leq X \leq 7) = P(X \leq 7) - P(X \leq 3)$

$P(X \leq x) = 1 - e^{-\mu x}$

$P(X \leq 7) = 1 - e^{-0.1*7} = 0.5034$

$P(X \leq 3) = 1 - e^{-0.1*3} = 0.2592$

$P(3 \leq X \leq 7) = P(X \leq 7) - P(X \leq 3) = 0.5034 - 0.2592 = 0.2442$

24.42% probability that the arrival time between customers will be between 3 and 7 minutes

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3 years ago

Which of the following is equivalent to 1/3(6x-12y) ?

harkovskaia [24]

1/3(6x-12y)
2x - 4y

the answer is A

5 0

3 years ago