Answer:
50000 4000 800 90 6
Step-by-step explanation:
there is the answer.
We're going to be using combination since this question is asking how many different combinations of 10 people can be selected from a set of 23.
We would only use permutation if the order of the people in the committee mattered, which it seems it doesn't.
Formula for combination:

Where
represents the number of objects/people in the set and
represents the number of objects/people being chosen from the set
There are 23 people in the set and 10 people being chosen from the set


Usually I would prefer solving such fractions by hand instead of a calculator, but factorials can result in large numbers and there is too much multiplication. Using a calculator, we get

Thus, there are 1,144,066 different 10 person committees that can be selected from a pool of 23 people. Let me know if you need any clarifications, thanks!
~ Padoru
Answer:
approximately 9
Step-by-step explanation:
6 squared (36) plus 8 squared (64) is 84, and the square root of that is about 9
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Answer:
1) Amy can invite 17 people.
2) x > 76
3) 40 - 6 is greater than or equal to 3x
4) x is greater than or equal to 98
Step-by-step explanation:
1) 50 + 8x = 200
2) 200 < 3x - 28
3) 40 = 6 +3x
4) (95 + 78 + 89 + x)/4 is greater than or equal to 90