A standard die is rolled 600 times. How many times would you expect to roll a number

2 answers:

5 0

Their are 3 numbers less than 4 on a die with 6 sides so 3 is 50% of 6 so then it should land on a number less than 4 50% of the 600 rolls to get 300

wel3 years ago

4 0

So a die has six sides, three of those sides are less than 4, so you would have a 1/2 chance of getting one of them.

Multiply 1/2 by 600 (which is the same as doing 600/2) to get 300.

Therefore, you would expect to roll a number less than four 300 out of 600 times.

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School started at 9:15am. After two period lasting 50min each, children had a break. At what time was the break?

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10:55

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3 years ago

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Which equation does the graph of the systems of equations solve?

mihalych1998 [28]

Answer:

$\text{B. }\frac{1}{3}x-3=-x+1$

Step-by-step explanation:

Let's start by taking a look at the blue line. The slope of any line that passes through two points is equal to the change in y-values over the change in x-values. We can see that the line passes through points (0, 1) and (1, 0). Assign these points to $(x_1,y_1)$ and $(x_2, y_2)$ (doesn't matter which you assign) and use the slope formula:

$m=\frac{y_2-y_1}{x_2-x_1}$

Let:

$(x_1,y_1)\implies (0,1)\\(x_2,y_2)\implies (1, 0)$

The slope is equal to:

$m=\frac{0-1}{1-0}=\frac{-1}{1}=-1$

Therefore, the slope of this line is -1. In slope-intercept form $y=mx+b$ , $m$ represents slope, so one of the lines must have a term with $-x$ in it, which eliminates answer choices A and D.

For the second line, do the same thing. The red line clearly passes through (0, -3) and (3, -2). Therefore, let:

$(x_1,y_1)\implies (0,-3)\\(x_2,y_2)\implies (3, -2)$

Using the slope formula:

$m=\frac{-2-(-3)}{3-0}=\frac{1}{3}$

Thus, the slope of the line is 1/3 and the other line must have a term with $\frac{1}{3}x$ in it, eliminating answer choice C and leaving the answer $\boxed{\text{B. }\frac{1}{3}x-3=-x+1}$