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Ainat [17]
3 years ago
5

A standard die is rolled 600 times. How many times would you expect to roll a number

Mathematics
2 answers:
jekas [21]3 years ago
5 0
Their are 3 numbers less than 4 on a die with 6 sides so 3 is 50% of 6 so then it should land on a number less than 4 50% of the 600 rolls to get 300
wel3 years ago
4 0
So a die has six sides, three of those sides are less than 4, so you would have a 1/2 chance of getting one of them.

Multiply 1/2 by 600 (which is the same as doing 600/2) to get 300.

Therefore, you would expect to roll a number less than four 300 out of 600 times.
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\large \mathfrak{Answer : }

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You are walking along a path y= 2x + 12 and your
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Answer:

(-1,10)

Step-by-step explanation:

At the point when the paths cross, the respective x and y values of each equation will be equal.

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3 0
3 years ago
Someone answer if it's correct I am going to give you brainliest
almond37 [142]
.48x =36 x=36/.48 x=75 So the total distance to kirk's grandmother's house was 75 miles
3 0
3 years ago
Read 2 more answers
The LCM of two numbers is 60. Their GCf is 6 and their difference is 18. What are the two numbers?
Aliun [14]
LCM(x,y)=60\\
GCF(x,y)=6\\
x-y=18\\\\
LCM(x,y)=\dfrac{|x\cdot y|}{GCD(x,y)}\\
60=\dfrac{|x\cdot y|}{6}\\
|x\cdot y|=360\\\\\\
|x\cdot y|=360\\
x-y=18\\\\
|x\cdot y|=360\\
x=18+y\\\\
|(18+y)\cdot y|=360\\
|18y+y^2|=360\\
18y+y^2=360 \vee 18y+y^2=-360\\
y^2+18y+81=441 \vee y^2+18y+81=-279\\
(y+9)^2=441 \vee (y+9)^2=-279\\
y+9=\sqrt{441} \vee y+9=-\sqrt{441}\\
y=21-9 \vee y=-21-9\\
y=12 \vee y=-30\\\\
x-12=18 \vee x-(-30)=18\\
x=30 \vee x=-12\\\\
\boxed{x=30, y=12 \vee x=-12, y=-30}
4 0
3 years ago
Read 2 more answers
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