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gogolik [260]
3 years ago
10

School started at 9:15am. After two period lasting 50min each, children had a break. At what time was the break?

Mathematics
2 answers:
pogonyaev3 years ago
6 0

Answer:

10:55

Step-by-step explanation:

9:15/10:05/10:55

Reptile [31]3 years ago
4 0

Answer:

10:55 AM

Step-by-step explanation:

50 minutes + 50 minutes = 100 minutes

9:15 am + 100 minutes = 10:55 AM

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If 2/3 + p = 1 and 4/5+ q = 3, what is the value of p+q?
inessss [21]

Answer:

p+q = 38/15

Step-by-step explanation:

2/3+p = 1. p = 1 - 2/3

4/5 + q = 3. q = 3 - 4/5

p + q = 1 - 2/3 + 3 - 4/5

-2/3 - 4/5 (common denominator = 15)

4 - 10/15 - 12/15 = 4 - 22/15

4 - 22/15 = (4*15 - 22)/15

= 38/15

5 0
2 years ago
Use substitution to solve the<br> following system of equations.<br> 8x + 3y = -22 AND y= -6x - 14
irinina [24]
This is the correct answer for the system of equations

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3 years ago
What is the length of missing side DE? Round answer to nearest tenth.
Oksi-84 [34.3K]

Answer:

Step-by-step explanation:

Considering the given triangle QED, to determine ED, we would apply the sine rule. It is expressed as

a/SinA = b/SinB = c/SinC

Where a, b and c are the length of each side of the triangle and angle A, Angle B and angle C are the corresponding angles of the triangle. Likening it to the given triangle, the expression becomes

ED/SinQ = EQ/SinD = QD/SinE

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3 years ago
The average number 1 0 1 5 6 3 4​
Kruka [31]
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4 0
3 years ago
Where are the asymptotes for the following function located? f (x) = StartFraction 7 Over x squared minus 2 x minus 24 EndFracti
Aleonysh [2.5K]

The the asymptotes are at x = -4 and 6.

Now we have given

f(x)=\frac{7}{x^2-2x-24}

f(x) = ∞, is not defined for x²- 2x - 24 = 0.

.What is the regular hyperbola?

A rectangular parabola is a hyperbola having three transverse axes and the conjugate axis of equal length. The arcs of a rectangular hyperbola are the same as the arc of the circle. The general equation of the rectangular hyperbola is x² + y² = a²

Given  function is a,

f(x)=\frac{7}{x^2-2x-24}

To find the asymptotes of a hyperbola.

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x^{2} - 2x - 24 = 0\\x^{2}  - (6-4) x - 24 = 0x^{2}  -6x + 4x -24 = 0( x - 6 ) ( x + 4 ) = 0

As the f(x) is not defined at -4 and 6.

Therefore,

The the asymptotes are at x = -4 and 6.

3 0
2 years ago
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