Answer:
D) g(x) = 4x^2 because the given point works when it's plug in the equation.
Step-by-step explanation:
It's a vertical stretch so a>1 for the transformation
Definitely not C, since it's a shrink with 0<a<1.
Plug in the point to see which one works
g(x) = 16x^2
g(1) = 16. A is not right
B is the same thing to A
g(1) = (4*1)^2 = 16. So, B is also not right
For D:
g(1) = 4(1)^2 =4. Point (1,4) that's show on the graph works for this equation.
D is correct
To find a 2-dimensional shape like a cylinder you say V=πr²h
to find a 3-dimensional shape like a sphere you will have V=4πr³÷3
Answer:
why would you put college and its g(t)= -16^2 +80t + 0
Step-by-step explanation:
this is because it is
