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mafiozo [28]
3 years ago
8

Roger goose had a 500-yard head start on willa. if willa's speed was 40 yards per second and roger's speed was only 20 yards per

second, how long did it take willa to catch up
Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
8 0
For this case what we should do is write the equation of movement for each person.
 We have then:
 For Roger:
 r = 20 * t + 500
 For Willa:
 r = 40 * t
 Equating the equations:
 20 * t + 500 = 40 * t
 We cleared t:
 40 * t - 20 * t = 500
 20 * t = 500
 t = 500/20
 t = 25 s
 Answer:
 
it did take willa 25 s to catch up Roger.
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8) through: (-3, -2), perp. to y = x – 1<br> A) y=-5x – 1 B) y=-4x – 5<br> C) y=-x – 5 D) y=-5x – 4
nexus9112 [7]

<u>Answer:</u>

The equation through (-3, -2) and perpendicular to y = x – 1 is y = -x -5 and option c is correct.

<u>Solution:</u>

Given, line equation is y = x – 1 ⇒ x – y – 1 = 0. And a point is (-3, -2)

We have to find the line equation which is perpendicular to above given line and passing through the given point.

Now, let us find the slope of the given line equation.

\text { Slope }=\frac{-x \text { coefficient }}{y \text { coefficient }}=\frac{-1}{-1}=1

We know that, <em>product of slopes of perpendicular lines is -1. </em>

So, 1 \times slope of perpendicular line =  -1

slope of perpendicular line = -1

Now let us write point slope form for our required line.

\mathrm{y}-\mathrm{y}_{1}=\mathrm{m}\left(\mathrm{x}-\mathrm{x}_{1}\right)

y – (-2) = -1(x – (-3))

y + 2 = -1(x + 3)

y + 2 = -x – 3

x + y + 2 + 3 = 0

x + y + 5 = 0

y = -x -5

Hence the equation through (-3, -2) and perpendicular to y = x – 1 is y = -x -5 and option c is correct.

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3 years ago
Simplify each expression -5r (3r^2)​
Evgen [1.6K]

Answer:

The answer you're looking for is

-5r (3r^2) = -45

Step-by-step explanation:

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The 2nd choice down in correct.
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______________________

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3

3 0
3 years ago
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