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mafiozo [28]
3 years ago
8

Roger goose had a 500-yard head start on willa. if willa's speed was 40 yards per second and roger's speed was only 20 yards per

second, how long did it take willa to catch up
Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
8 0
For this case what we should do is write the equation of movement for each person.
 We have then:
 For Roger:
 r = 20 * t + 500
 For Willa:
 r = 40 * t
 Equating the equations:
 20 * t + 500 = 40 * t
 We cleared t:
 40 * t - 20 * t = 500
 20 * t = 500
 t = 500/20
 t = 25 s
 Answer:
 
it did take willa 25 s to catch up Roger.
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anzhelika [568]
Absolutely no clue but someone out there does
4 0
3 years ago
A bag contains yellow balls, pink balls and green balls only.
topjm [15]

Answer:

90

Step-by-step explanation:

M1 for ( ) 42/7 [x(7+3+5)] soi by 6

=90

3 0
3 years ago
It says 7/6x= 140 I am lost can somebody please help me
kobusy [5.1K]
7/6x=140

since variable x is multiplied by 7/6, find x by multiplying by the inverse of 7/6 which is 6/7.

7/6x × 6/7 = 140 × 6/7
x= 120
8 0
3 years ago
Please help. I'm dumb and can't understand this.
Fed [463]

Answer: 5 years

              14,800 students enrolled

Step-by-step explanation:

Let x represent the number of years and

Let y represent the number of students enrolled

College A: y = 12,300 + 500x

College B: y = 18,550 - 750x

Use substitution Method to solve:

12,300 + 500x = 18,550 - 750x

            +750x                +750x

12,300 + 1250x = 18,550

-12,300               -12,300

              1250x = 6250

                      x = 5

Input x = 5 into one of the equations to solve for y.

y = 12,300 + 500x

  = 12,300 + 500(5)

  = 12,300 + 2500

  = 14,800

Read more on Brainly.com - brainly.com/question/12387804#readmore

8 0
3 years ago
Read 2 more answers
How to solve this problem??
slega [8]
\frac{2}{3} =  \frac{18}{x+5}

multiply each side by x+5
\frac{2x+10}{3}=18
multiply each side by 3

8 0
3 years ago
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