Someone help!!!!! Which graph is defined by the function given below? y = (x - 2)(x -5)

Mathematics

1 answer:

Artemon [7]3 years ago

6 0

Post a picture of the graphs it shows

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What is the interquartile range (IQR) of the following data set?

OleMash [197]

Answer:

Step-by-step explanation:

Arrange data set

19, 4, 17, 3, 6, 5,5, 3, 11, 12, 3, 7, 15, 8, 8, 10,5, 3, 12, 41, 36

in ascending order

3, 3, 3, 3, 4, 5, 5, 5, 6, 7, 8, 8, 10, 11, 12, 12, 15, 17, 19, 36, 41

The median is $Q_2=8$

$Q_1=\dfrac{4+5}{2}=4.5$

$Q_3=\dfrac{12+15}{2}=13.5$

Thus, the interquartile range is

$Q_3-Q_1=13.5-4.5=9$

4 0

4 years ago

You are saving $5 each week to attend a summer program that costs $300. You already have $84. You have also received a $50 schol

rosijanka [135]

D.34 more weeks left of saving because you have $166 more dollars to go after your $50 dollar scholarship program and the 16 weeks of saving $84 dollars.

6 0

3 years ago

A machine fills 75 bottles of water each minute. Write an equation to represent the number of bottles b of water the machine can

Len [333]

Answer:

b = 75m

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

How can you solve this problem 2250=5000 x R x 5

vesna_86 [32]

R is equal to 450

first you subtract 5000 from each side

-2250=Rx5
then divid by 5

R=450

5 0

3 years ago

Allan borrows 1870 dollars from his uncle. Two years later, he borrows another 1240 dollars. If his uncle charges him 8 percent

Anna11 [10]

For t=0
Allan borrows--------------------------- > 1870 dollars

for t=6 years
F1 = P*(1 +(r/m))^n
i=r/m
n=m*t---------- >1*6=6
we have
P1=1870
r=8%
m=1
t=6 years
F1 = 1870*(1 +(0.08/1))^6------------------ >2967.45 dollars

for t=2
Allan borrows--------------------------- > 1240 dollars

for t=6 years
F2 = P2*(1 +(r/m))^n
i=r/m
n=m*t---------- >1*4=4
we have
P2=1240
r=8%
m=1
t=4 years------------> (6-2)=4 years
F2 = 1240*(1 +(0.08/1))^4------------------ >1687 dollars

F1+F2=2967.45+1687=4654.45 dollars
the answer is 4654.45 dollars

3 0

4 years ago