Question

A game has a rectangular board with an area of 44in2. There is a square hole near the top of the game board in which you must not toss in a bean bag. The square has side lengths of 3in. What is the probability of tossing the bag through the hole?

Answer 1

Answer: Probability of tossing the bag through the hole = $\frac{9}{44}$

Step-by-step explanation:

Since we have given that

A game has a rectangular board with an area of 44 in².

There is a square hole near the top of the game board in which you must not toss in a bean bag.

Length of Side of a square = 3 in.

So, Area of square of square is given by

$Area=Side\times Side\\\\=3\times 3\\\\=9\ in^2$

So, Probability of tossing the bag through the hole will be

$\frac{\text{Number of favourable outcome}}{\text{ Total number of outcomes }}\\\\=\frac{9}{44}$

Hence, Probability of tossing the bag through the hole = $\frac{9}{44}$

Answer 2

9/44 chance of tossing it through the hole.