We have the following equation:
3x2 + 7x + 4 = 0
Using the resolver we have:
x = (- b +/- root (b2 - 4ac)) / 2a
Substituting values we have:
x = (- (7) +/- root ((7) 2 - 4 (3) (4))) / 2 (3)
Rewriting:
x = (- 7 +/- root (49 - 48)) / 6
x = (- 7 +/- root (1)) / 6
x = (- 7 +/- 1) / 6
The results are:
x = (- 7 + 1) / 6 = -6/6 = -1
x = (- 7 - 1) / 6 = -8 / 6 = -4/3
Answer:
x = -1
x = -4/3
option C and D
Answer:
sss therom
Step-by-step explanation:
they are congruent on all sides
Answer:
Step-by-step explanation:
hello :
r+b=7... (*)
3.75r+2.75b=22.25.... (**)
use (*) : r = 7 - b
put this value in (**) :
3.75(7 - b)+2.75b = 22.25
26.25 -375b +2.75b = 22.5
-375b +2.75b = 22.5 - 26.25
- b = -3.75
so : b = 3.75
but : r = 7 - b
r = 7 - 3.75
r = 3.25
Answer:a=2.1 :)
Step-by-step explanation:a+(-1.6)=-3.7
+1.6 +1.6
a=-2.1
