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3 years ago

What is the following difference? 11 square root 45 - 4 square root 5

Mathematics

2 answers:

Zinaida [17]3 years ago

5 0

Answer:

$29\sqrt{5}.$

Step-by-step explanation:

The difference is

$11\sqrt{45}-4\sqrt{5}$

To simplify let's try to covert $\sqrt{45}$ in terms of $\sqrt{5}$ :

45 = 9*5, then $\sqrt{45} = \sqrt{9*5} = \sqrt{9}\sqrt{5} = 3\sqrt{5}$ . So,

$11\sqrt{45}-4\sqrt{5} = 11(3\sqrt{5})-4\sqrt{5} = 33\sqrt{5} -4\sqrt{5} = 29\sqrt{5}.$

Fofino [41]3 years ago

4 0

11√45 - 4√5

= 11√(9 * 5) - 4√5

= (11 · √9 · √5) - 4√5

= (11 · 3 · √5) - 4√5

= (11 * 3)√5 - 4√5

= 33√5 - 4√5

= (33-4)√5

= 29√5

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I'm really not sure how to go about solving this algebraic equation, please help! .513 = (2x)^2 / (.05-x)

LiRa [457]

Let's set it up like this:
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Multiply both sides by $0.05-x$
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The variable $x$ can be both positive or negative.
We have found successfully our answer.

Let me know if you have any questions regarding this problem!
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