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Arturiano [62]
3 years ago
7

What is the following difference? 11 square root 45 - 4 square root 5

Mathematics
2 answers:
Zinaida [17]3 years ago
5 0

Answer:

29\sqrt{5}.

Step-by-step explanation:

The difference is

11\sqrt{45}-4\sqrt{5}

To simplify let's try to covert \sqrt{45} in terms of \sqrt{5}:

45 = 9*5, then \sqrt{45} = \sqrt{9*5} = \sqrt{9}\sqrt{5} = 3\sqrt{5}. So,

11\sqrt{45}-4\sqrt{5} = 11(3\sqrt{5})-4\sqrt{5} = 33\sqrt{5} -4\sqrt{5} = 29\sqrt{5}.

Fofino [41]3 years ago
4 0
11√45 - 4√5

= 11√(9 * 5) - 4√5

= (11 · √9 · √5) - 4√5

= (11 · 3 · √5) - 4√5

= (11 * 3)√5 - 4√5

= 33√5 - 4√5

= (33-4)√5

= 29√5
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Answer:

  (x, y) = (-3 5/8, 1 5/16)

Step-by-step explanation:

Add y+14 to the second equation to get ...

  3.5x +14 = y

Substitute this for y in the first equation:

  2.5x -3(3.5x +14) = -13

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  -8x = 29

  x = -29/8 = -3 5/8

Using this in the formula for y, we get ...

  3.5(-29/8) +14 = y

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Solve: s = 4 + √ s + 2<br><br> a. s=2<br> b. s=7<br> c. s=2 or s=7<br> d. no real solution
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#3 a. g(-1) = 2, g(0) = 3, and g(1) = 2

b. No restrictions for all real numbers

\#4 \  a. \ h(-1) = \dfrac{1}{3}, \  h(0) =0, \  h(2) =  \infty

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Step-by-step explanation:

#3 The function is given as g(x) = -x² + 3

a. From the given function, by plugging in the value of 'x' in the bracket, we have;

g(-1) = -(-1)² + 3 = -1 + 3 = 2

g(-1) = 2

g(0) = -0² + 3 = 3

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g(1) = 2

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b. The given function g(x) = -x² + 3 for finding the value of <em>g</em> can take any value of <em>x</em> which is a real number

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\therefore h(-1) = \dfrac{1}{3}

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b. From the values of the function, we have that h(x) is not defined at x = 2

Therefore, there is a restriction for <em>x</em> in the function, which is <em>x ≠ 2</em>

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