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Firlakuza [10]
3 years ago
7

Please do not answer unless you are pretty sure. Thanks!

Mathematics
1 answer:
Aleksandr [31]3 years ago
3 0
The enclosed diagram below shows the box diagram for the supplied data
 Population size: 12
 Medium: 54
 Lowest value: 40
 Highest value: 81
 First quartile: 43
 Third quartile: 76.25
 Interquartile range: 33.25
 With this information we can infer that the correct option is option 2, since it is the only diagram where the third quartile is greater than 76.

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The length of a rectangle is one foot more than twice its width if the area of the rectangle is 300 ft^2 find the dimensions of
umka21 [38]
Let's say the length is L, and the width is W
L is one foot more than 2W, so L=1+2W
the area of the rectangle: A=L*W=300
replace L with 1+2W: (1+2W)*W=300 =>2W^2+W-300=0
solve the quadratic equation: (W-12)(2W+25)=0
W=12 or W=-12.5 (impossible)
so the width is 12, and the length is L=1+2*12=25

please refer to this website for how to factor a quadratic equation
http://www.purplemath.com/modules/factquad.htm

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zvonat [6]

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3x^2y^5 * 4x^3y^7

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Put them back together

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What is the area of this figure in square meters I’ll mark you brainlidt
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