1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
butalik [34]
3 years ago
10

What is the sum of .5 and .3 repeating

Mathematics
2 answers:
vovangra [49]3 years ago
8 0
.8 repeating. I believe is this answer.


kondaur [170]3 years ago
5 0
8 repeating......... .....
You might be interested in
Solve for b 2 in A = h(b 1+b 2), if A = 16, h = 4, and b 1 = 3. b 2 =
hammer [34]

Answer:

b2 = 1

Step-by-step explanation:

A = h(b1 + b2)

Given:

A = 16

h = 4

b1 = 3

b2 = x

Work:

A = h(b1 + b2)

16 = 4(3 + x)

16 = 12 + 4x

4x = 16 - 12

4x = 4

x = 1

4 0
3 years ago
The mean price of a new laptop computer from Store #1 is $799.99, and they only sell two brands of computers. The mean price of
Sati [7]
<span>                                                     value
Weighted mean average = ---------------------------
                                              number of brands


value = mean price of computers from Store #1 * number of brands from store #1 + mean price of computers from store #2 * number of brands from store #2

value =  $799.99 * 2 +  $679.99 * 4 = $4,319.94

number of brands = 2 + 4 = 6

weighted average = $4,319.94 / 6 = $ 719.99

Answer: option b. $719.99
</span>
6 0
2 years ago
The ages of the winners of a cycling tournament are approximately bell-shaped. The mean age is 27.2 years, with a standard devia
elena-14-01-66 [18.8K]

Answer:

a. z-score = -1.2

b. The age 23 years old is -1.2 standard deviations below the mean

c. The age is not unusual

Step-by-step explanation:

a. Transformation to z-score

Mathematically;

z-score = (x - μ)/σ

where σ and μ are the standard deviation and the mean respectively.

From the question, x = 23, μ = 27.2 and σ = 3.5

Let’s put these into the equation;

z-score = (23-27.2)/3.5 = -1.2

b. Interpretation of result

The interpretation is that 23 years old is -1.2 standard deviations below the mean

c. Determination

The age is not unusual. This is because any z-value below -2 or above 2 is considered unusual

-1.2 is above -2 and thus it is not unusual

7 0
2 years ago
I NEED HELP NOW!!!! Please this is Due!!
Sladkaya [172]

Answer:

85 quarters and 135 dimes

Step-by-step explanation:

its basically a guess and check

formula - 0.25q + 0.10d = $34.75

0.25 x 85 + 0.10 x 135 = 34.75

8 0
3 years ago
What percent of 4c in each expression? <br> 0.2c
Ymorist [56]

The percentage of 4c in the expression 0.2c is 2000%

<h3>How to determine the percentage of 4c?</h3>

The expression is given as:

0.2c

The percentage of 4c is then calculated as:

4c/0.2c

Evaluate the quotient

20

Express as percentage

2000%

Hence, the percentage of 4c in 0.2c is 2000%

Read more about percentages at:

brainly.com/question/843074

#SPJ1

7 0
1 year ago
Other questions:
  • If y varies directly as x and k = 8, find x when y = 8<br><br> 1. 1<br> 2. 8<br> 3. 64
    5·1 answer
  • Evaluate the expression 4/15÷x+0.4 for x if: x=1, x=4/9, x=1 1/3. Solve for each X. I need help Will give brainliest!
    6·1 answer
  • 20x + 35y. What is the greatest common factor of the terms 20x and 35y?
    15·2 answers
  • What is the smallest number that has 1,2,3,4, and 5 as factors
    8·1 answer
  • What is the value of m?<br> O 10<br> O 30<br> O 70<br> O 150
    10·1 answer
  • Write down the converse and contrapositive. If 2 divides x, then x is an even number. Hint call this (p?q)
    10·1 answer
  • HELPPPPP AGAIN please
    15·1 answer
  • What letter is used to represent scale factor ?
    13·1 answer
  • Help. Me. Please. I don't understand it!! Asap please!
    9·2 answers
  • Aleesia has a box of 52 muffins. She wants to put out plates that each have the same number of muffins. What is one possible way
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!