Is a biased sample valid
1 answer:
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Answer:
Step-by-step explanation:
Given is a function as
Equating to 0 we have equation
If the function f(x) has x intercepts then the solutions are real
Let us use remainder theorem and change of signs rule
f(0) = 1>0
f(-1) = -1+3+1=3
f(-2) = -32+6+1<0
This implies there is a real root between -1 and -2.
f(1) = -1
Since f(0) and f(1) have different signs, there exists a real root between 0 and 1.
f(2) = 32-6+1>0
Since f(1) and f(2) have different signs there exists a real root between 1 and 2.
Thus there are definitely three real solutions as
one between -1 and 0, one between 0 and 1, and third between 1 and 2.
<h3>━━━━━━❃━━━━━━</h3><h3>Part one :</h3>
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As it is given :
Present age of mom : Present age of son = 6 : 1
Therefore let :
- Mother's age be 6x
- Son's age be x
Ages after 10 year :
- Mom's age = 6x + 10
- Son's age = x + 10
The ages after 10 years are given in rational of 8 : 3.
Which means :
Mom's age after 10 years : Son's age after 10 years = 8 :3.
Now :
So :
We know :
And all we are done ! ㋛
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