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Ghella [55]
3 years ago
15

Chloe is working two summer jobs, landscaping and clearing tables. She must work no less than 12 hours altogether between both j

obs in a given week. Write an inequality that would represent the possible values for the number of hours landscaping, ll, and the number of hours clearing tables, cc, that Chloe can work in a given week.
Mathematics
1 answer:
Jet001 [13]3 years ago
8 0

Answer:

L + C \ge 12

Step-by-step explanation:

L = hours landscaping

C = hours clearing tables

The sum of the hours must be no less than 12, so it must be 12 or more.

L + C \ge 12

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Calculate the slope of a line that passes through the points (-4,7) and (-1,3)
zmey [24]

Answer:

The answer is

-  \frac{4}{3}  \\

Step-by-step explanation:

The slope of a line given two points can be found by using the formula

m =  \frac{ y_2 - y _ 1}{x_ 2 - x_ 1} \\

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(-4,7) and (-1,3)

We have

m =  \frac{3 - 7}{ - 1 -  - 4}  =  \frac{ - 4}{ - 1 + 4}  =   -  \frac{4}{3}  \\

We have the final answer as

-  \frac{4}{3}  \\

Hope this helps you

4 0
3 years ago
Please help me‼️‼️‼️‼️‼️‼️‼️‼️‼️
galina1969 [7]

Step-by-step explanation:

1 m = 3.280839895... ft

therefore,

1 m² = 10.76391042... ft²

35 m² = 35 × 10.76391042... ft² =

= 376.7368646... ft²

the area of the circle is

pi×r²

r = 50/2 = 25 ft

so, the area of the red circle is

pi×25² = pi×625 = 1,963.495408... ft²

we need to paint it twice, so the area to be painted is twice the area of the circle

2×pi×625 = 3,926.990817... ft²

we need a many cans as the cover area of a single can fits into the total area to be painted :

3,926.990817... / 376.7368646... = 10.42369671... cans

we need to round this up to full cans.

so, we need 11 cans of red paint to give that red pad 2 coats of paint.

7 0
2 years ago
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Answer:

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Step-by-step explanation:

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2m - 5m³ - 5m - 3m³ + 7m^4 + 8 - 3m³ - 5m^4 + 4m

7m^4 - 5m^4 - 5m³ - 3m³ - 3m³ + 2m - 5m + 4m + 8

2m^4 - 11m³ + m + 8

6 0
3 years ago
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Answer:

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