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Brums [2.3K]
4 years ago
8

Help i dont know math! what is Maht?

Mathematics
1 answer:
snow_lady [41]4 years ago
6 0
What's your question? 
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What angle relationship describes VQR and QRW?
Vlad [161]

Answer: alternate interior angles

Step-by-step explanation:

Got it Right on the test. :)

8 0
3 years ago
Let f(x)=x^2-5x+8 and g(x)=x^2-4 (f-g)(x)=
Bogdan [553]
What you do here is subtract g from f: x^2 - 5x + 8 - (x^2 -4); x^2 - 5x + 8 - x^2 + 4; Rearranging gives you x^2 - x^2 - 5x + 8 + 4 which is, simplified, -5x + 12
8 0
3 years ago
A mother gives birth to a 9 pound baby. every 4 months, the baby gained 2 pounds. if x is the age of the baby in months, then y
chubhunter [2.5K]
For the equation of the line of the form y = mx + b, m is the slope of the line and b is the y-intercept which is the value of y when x is equal to zero. The slope is the rate of change of y per change in x. "y" would represent the dependent variable which is the weight of the baby while "x" represents the independent variable which is the number of months or the age of the baby in months. We calculate the slope as follows:

slope = (11 - 9) / ( 4 - 0) = 2/4 = 0.5
at x = 0, it is said that the weight of the baby is 9 lbs so the value of b would be 9.

The equation of the line would be y = 0.5x + 9
6 0
3 years ago
What are 2 equivalent ratios to 27:9?​
Andrei [34K]

Answer:

3:1

54:18

Step-by-step explanation:

You can divide both sides by 9 to get one ratio:

27/9:9/9

3:1

You can also multiply both sides by 2 to get another ratio:

27(2):9(2)

54:18

8 0
3 years ago
What is the kinetic Energy of a 110 kg linebacker rushing towards his football
Leviafan [203]

<u>Answer:</u>

The Kinetic energy of the 110 kg linebacker is 1375 J

<u>Solution:</u>

The kinetic energy of an object is the energy produced by its velocity. Kinetic energy of an object is directly proportional to the mass and the square of the its velocity.

Therefore, the formula for kinetic energy is

KE=\frac{1}{2} \times m v^{2}

Here, The linebacker’s mass m = 110 kg

The linebacker’s velocity v = 5 m/s

So by substituting the values,

The kinetic energy of linebacker is

K E=\left(\frac{1}{2} \times 110 \times 5 \times 5\right) \text { Joules } \\\\ \Rightarrow (\frac{2750}{2}) Joules = 1375 Joules

3 0
3 years ago
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