All categories

3 years ago

Solve for K: 248 - 4K = 5 + 9(-3+4)

2 answers:

4 0

Our original equation:
$248 - 4k = 5+9(-3+4)$
Now, we just solve for k:
When we use PEMDAS, we get this equation:
$248 - 4k = 14$
Now, subtract 248 from both sides:
$- 4k = -234$
Now, divide -4 on both sides:
$k = 58.5$
The answer to your problem is k = 58.5 or k = 117/2. Hope this helps and have a fantastic day!

Anastaziya [24]3 years ago

4 0

K= 58.5 I hope this helps

You might be interested in

Identify the graph of y=x3.

77julia77 [94]

Answer:

2nd Graph

Step-by-step explanation:

6 0

4 years ago

Read 2 more answers

Figure LMNP will be reflected across the y-axis. Place the point on the graph that represents

zimovet [89]

Answer:

If it's reflected on the y-axis, the answer for N would be (-2,-3).

5 0

3 years ago

37. Construct Arguments Luis and Raul are

Katarina [22]

Using the slope - intercept relation, the required equation which models the scenario and Raul's speed are ;

y = - 7.5x + 15
4 miles per hour

Time difference, Δt = 1.2 hours - 0.5 hours = 0.7 hours

Change in distance, Δd = 11.25 - 6 = 5.25 miles

Assuming a constant speed :

Speed = (Δd ÷ Δt) = (5.25 ÷ 0.7) = 7.5 mi/hr

Using the general form :

y = bx + c

At, x = 1.2 hours ;

Miles left, y = 6 miles

End point decreases by 7.5 mi/hr (-7.5 mi/hr)

Inputting the data into the equation :

6 = - 7.5(1.2) + c

6 = - 9 + c

c = 6 + 9 = 15 miles

The expression in slope intercept form becomes ;

y = -7.5x + 15

If Raul lives 5 miles closer to the beach ;

Time it will take Luis to get to the beach :

Time taken = (15 ÷ 7.5) = 2.5 hours

Distance Raul has to cover = 15 - 5 = 10 miles

To reach the beach after 2.5 hours ;

Speed required = (10 ÷ 2.5) = 4 mi/hr

Therefore, Raul has to ride at 4 miles per hour for the plan to work.

Learn more :brainly.com/question/18405415

5 0

3 years ago

An airline's public relations department claims that when luggage is lost, 88% is recovered and delivered to its owner within 24

melisa1 [442]

Answer:

The hypothesis statements are: H0: p = 0.88 versus HA : p < 0.88

The p-value of the test is 0.2483 > 0.1, which means that the data does not provide sufficient evidence to conclude that the proportion of times that luggage is returned within 24 hours is less than 0.88.

Step-by-step explanation:

Test if the proportion of times that luggage is returned within 24 hours is less than 0. 88

At the null hypothesis, we test if the proportion is of 0.88, that is:

$H_0: p = 0.88$

At the alternate hypothesis, we test if this proportion is less than 0.88, that is:

$H_a: p < 0.88$

The hypothesis statements are: H0: p = 0.88 versus HA : p < 0.88

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

0.88 is tested at the null hypothesis:

This means that $\mu = 0.88, \sigma = \sqrt{0.88*0.12}$

A consumer group who surveyed a large number of air travelers found that 138 out of 160 people who lost luggage on that airline were reunited with the missing items by the next day.

This means that $n = 160, X = \frac{138}{160} = 0.8625$