Answer:
pqr are similar tringle
Step-by-step explanation:
n=triangle are solve by n
bastahan na toh
0.0038 is the probability that the code is 9Z.
<u>Step-by-step explanation:</u>
Here we have , A code consists of a digit chosen from 0 to 9 followed by a letter of the alphabet. We need to find What is the probability that the code is 9Z . Let's find out:
A code consists of a digit between 0-9 , i.e. there are 10 choices . And followed by a letter i.e. from A-Z having 26 choices ! So combinations possible are :
0{A-Z}=26
1{A-Z} = 26
2{A-Z} = 26
3{ A-Z}=26
.......
9{A-Z}=26 or ,
⇒ 10(26)
⇒ ![260](https://tex.z-dn.net/?f=260)
Now , 9Z is one combination ! So , probability :
⇒ ![\frac{1}{260}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B260%7D)
⇒ ![0.0038](https://tex.z-dn.net/?f=0.0038)
Therefore , 0.0038 is the probability that the code is 9Z.
Answer: 196
Step-by-step explanation:
As per given , we have
Population standard deviation: ![\sigma=0.6\ lb](https://tex.z-dn.net/?f=%5Csigma%3D0.6%5C%20lb)
Significance level : ![\alpha: 1-0.98=0.02](https://tex.z-dn.net/?f=%5Calpha%3A%201-0.98%3D0.02)
Using the z-value table , the critical z value for 98% confidence : ![z_{\alpha/2}=2.33](https://tex.z-dn.net/?f=z_%7B%5Calpha%2F2%7D%3D2.33)
Margin of error : E= 01 lb
Sample size : ![n=(\dfrac{z_{\alpha/2}\cdot\sigma}{E})^2](https://tex.z-dn.net/?f=n%3D%28%5Cdfrac%7Bz_%7B%5Calpha%2F2%7D%5Ccdot%5Csigma%7D%7BE%7D%29%5E2)
![n=(\dfrac{(2.33)\cdot(0.6)}{0.1})^2](https://tex.z-dn.net/?f=n%3D%28%5Cdfrac%7B%282.33%29%5Ccdot%280.6%29%7D%7B0.1%7D%29%5E2)
Simplify , we get
![n=195.4404\approx196](https://tex.z-dn.net/?f=n%3D195.4404%5Capprox196)
Hence, the minimum sample size required for books = 196