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aniked [119]
3 years ago
15

The scence fair The science fair projects are set up on tables. There are 99 long tables used. Each long table holds 7 projects.

The rest of the projects are set up on short tables. Each short table can hold 4 projects. What is the fewest number of short tables that will be needed for the rest of the projects? 202. 203. 354. 355
Mathematics
1 answer:
SashulF [63]3 years ago
5 0
I'm not for sure but I think it is 202
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Please someone help! You have to make this word problem into an inequality.
labwork [276]

Answer:

the theater needs to sell at least 100 tickets

Step-by-step explanation:

wants to make at least $1000 and they already have $50, so you take the $9.50 per ticket and add that to the $50.

$1000=$9.50t+$50

1000/50=9.5t

950=9.5t

950/9.5=t

t=100

4 0
3 years ago
What is 5r^2 = 80<br><br> It says solve each equation with the quadratic formula.
katovenus [111]
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5 0
3 years ago
Walk fifty meters at 30o north or east from the old oak tree. (2) Turn 45o to your left (you should now be facing 75o north of e
saw5 [17]

Answer:

A straight line of approximately 75 meters, 1.4º north

Step-by-step explanation:

Hi, let's make it step by step to make it clearer

1) If we walk 50 meters in 30º angle Northeast, assuming the Old Oak tree is the point 0,0 and we're dealing with vectors in R^{2}. To say 30º Northeast is 30º clockwise (or 60º counter clockwise).

2) Then there was a the turning point to the left. If I turn to the left, on my compass 45º , I'll face 75º northeast.

3) Finally, the last vector leads to the treasure from the Old Oak Tree, i.e. the resultant.

So, let's calculate the norm which is the length of the each vector.

1) Graphing them we can find the points, then the components and then calculate the norm, the length of each vector.  

Since the Oak Tree is on (0,0). The turning point (50,86.61) and the Rock (R=(1.4,74,85) we can write the following vectors:

\vec{u}=\left \langle 50,86.61 \right \rangle\\\vec{v}=\left \langle -48.6,-11.76\right \rangle\\\vec{w}=\left \langle 1.4,74.85 \right \rangle

Now, let's calculate each vector length by calculating the norm.

\left \| \vec{u} \right \|=\sqrt{50^{2}+86.6^2}=100\\\left \| \vec{v} \right \|=\sqrt{(-48.6)^2+(-11.76)^2}=50\\\left \| \vec{u} \right \|=\sqrt{(1.4)^2+(74.85)^2}=74.86

The path is almost 75 meters. And since it is less than 15º degrees to the left of the North (or to the right) its direction is still north of the Old Oak Tree.

8 0
3 years ago
Which of these represents slope-intercept form?
Alexxandr [17]

Answer:

Y=mx+b

Step-by-step explanation:

mx = slope

b = intercept (the place where the line hits the y axis)

6 0
3 years ago
Read 2 more answers
Jacob makes a scale drawing for a crate with a scale factor of 1:20. The dimensions of his scale drawing are 3 inches long by 2
kipiarov [429]

Answer: 6 inches long and 4 inches wide

Step-by-step explanation: The dimensions of the actual crate are 20 times those on Jacob's drawing. The dimensions on the builder's drawing are 1/10 of those, so (1/10)(20) = 2 times the dimensions on Jacob's drawing.

hope this helps

6 0
2 years ago
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