Independent variable (IV): something the scientist can change.
Thus, in this case, the IV can be the weight of the person.
![\bf Step-by-step~explanation:](https://tex.z-dn.net/?f=%5Cbf%20Step-by-step~explanation%3A)
Keep in mind: The entire line segment (VX) is equal to 14.
![\bf Step~1:](https://tex.z-dn.net/?f=%5Cbf%20Step~1%3A)
Let's see how the line segment looks like first.
Line segment VX is 14 units long.
14
______________
V X
W is on the line segment somewhere, and VW is equal to 3.
3 ?
______________
V W X
![\bf Step~2:](https://tex.z-dn.net/?f=%5Cbf%20Step~2%3A)
We have to solve for the <em>?.</em> Let's put ? as x. So now we are solving for x.
We have to set up our equation like this:
x + 3 = 14
Since our unknown value plus 3 is equal to 14, we have to subtract 3 from 14 to get our answer.
14 - 3 = 11
3 11
______________
V W X
![\large\boxed {\bf Our~final~answer: ~WX=11}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%20%7B%5Cbf%20Our~final~answer%3A%20~WX%3D11%7D)
Answer
19 people
Step by step explanation
C=pi d
C= 3.14(36)
C= 113.04
113.04 divided by 6 equals 18.84 or 19 people
It very well could be, but not necessarily. What if q = 10, s = 8, and t = 6?
The statement is that q is less than s, and s is less than t (which therefore also means q is less than t).
However, when we substitute (replace) all the letters with the values we assigned them, we can find that the expression becomes:
10 < 8 < 6
This clearly isn’t right, as 10 is the greatest number there, and 8 is definitely less than 10 and greater than 6.
Answer:
(See explanation for further details)
Step-by-step explanation:
The expression is transformed into its standard form:
![x^{2} + y^{2} - 6\cdot x + 10\cdot y + 34 = 0](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%2B%20y%5E%7B2%7D%20-%206%5Ccdot%20x%20%2B%2010%5Ccdot%20y%20%2B%2034%20%3D%200)
![x^{2} - 6\cdot x + 9 + y^{2} + 10\cdot y + 25 = 0](https://tex.z-dn.net/?f=x%5E%7B2%7D%20-%206%5Ccdot%20x%20%2B%209%20%2B%20y%5E%7B2%7D%20%2B%2010%5Ccdot%20y%20%2B%2025%20%3D%200)
![(x-3)^{2} + (y+5)^{2} = 0](https://tex.z-dn.net/?f=%28x-3%29%5E%7B2%7D%20%2B%20%28y%2B5%29%5E%7B2%7D%20%3D%200)
The function does not represent a circle, as radius is a positive number.