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ivann1987 [24]
3 years ago
15

How many sides does a decagon have

Mathematics
2 answers:
Ksju [112]3 years ago
7 0

A decagon would have ten sides.
Vladimir79 [104]3 years ago
3 0
Deca means 10, so therefore a decagon has 10 sides
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Write a decimal between 0.5 and 0.75.Then write it as a fraction in simplest form and as a percent
Andre45 [30]
You can do anything between .50 and .75. For example .55. .55=55% .55 also equals 11/20 as a fraction
8 0
3 years ago
How many years will it take for the account to reach $18,600? Round your answer to the nearest hundredth
Margarita [4]
 <span>it depends how the interest is calculated, but there's not much of a difference 

assuming its continuously compouned, you use this formula: A(t)=Pe^(rt), where A is the final amount, P is the initial investment, r is the interest, and t is the time in years 

you want to find t such that A(t)=18,600 so 18,600=1000e^(.0675t) 

you need to use logarithm to figure it out, take the natural log of both sides 

the following properties will come into use: 

ln(a*b)=ln(a)+ln(b) 
ln(a^b)=bln(a) 
ln(e)=1 

taking the natural log 

ln(18,600)=ln(1000e^(.0675t)) 

ln(18,600)=ln(1000)+ln(e^.0675t) 

ln(18600)=ln(1000) + .0675t 

now solve for t: t= (ln(18600)-ln(1000))/.0675 

t=43.31</span>
4 0
3 years ago
1) A bag contains six red marbles and eight blue marbles. You randomly pick a marble and then pick a second marble without retur
Elena-2011 [213]

Answer:

You would have 4 red marbles and 8 blue marbles since you didn't return the ones you took out to the bag.

Step-by-step explanation:

6 - 2 = 4

The 8 would stay the same

There for you would have 4 red marbles and 8 blue marbles left in the bag. Totalled you have 12 marbles in the bag and 2 out of the bag. (8 + 4 = 12)

Including the marbles in and out of the bag you have 14 marbles. The 12 inside the bag + the 2 outside of the bag = 14 marbles totalled.

5 0
3 years ago
What is 0.12 with 12 repeating as a fraction
strojnjashka [21]
12/99 is the fraction form
8 0
3 years ago
Read 2 more answers
A menu has five choices of appetizers
Vinil7 [7]

The number of the meals possible is 350.

The complete question is given below:-

A menu has 5 choices of appetizers, ten main courses, and seven desserts. How many meals are possible?

<h3 /><h3>What is the combination?</h3>

The arrangement of the different things or numbers in a number of ways is called the combination.

Given that:-

  • A menu has 5 choices of appetizers, ten main courses, and seven desserts.

The number of the combination of the meals will be calculated as:-

N = 5 x 10 x 7

N = 350

Therefore the number of the meals possible is 350.

To know more about combinations follow

brainly.com/question/11732255

#SPJ1

3 0
1 year ago
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