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Vesna [10]
3 years ago
10

Does the graph represent a function?

Mathematics
2 answers:
stiv31 [10]3 years ago
6 0
No it does not. Any function that has any of the same X vaules (The line going up left to right) is not a function.
11Alexandr11 [23.1K]3 years ago
4 0

Answer:

The graph doesn't represent a function.

Step-by-step explanation:

Consider the provided graph.

A graph is said to be a function if for each value of x we can get different y value or each input (x) has a single output (y).

Now, observe the graph.

The value x = -5 is related to more than one value of the y.

For x = -5 we have different y values.

For example (-5,0), (-5,1), (-5,2),(-5,3) all these values satisfy the graph. Thus the graph is not a function.

We can prove it by a vertical line test.

Vertical line test: If a vertical line intersects the graph more than once, then the graph is not a function.

Now if we draw a vertical line at x=-5 it will intersect the graph more than once, therefore, the provided graph is not a function.

Hence, the graph doesn't represent a function.

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Does anyone know this and if it is extraneous or not?
Anna11 [10]
Addd 4 to both sides
\sqrt{x+9}=5
sqare both sides
x+9=25
minus 9 both sides
x=16

plug it in for x and see
\sqrt{16+9}-4=1
\sqrt{25}-4=1
5-4=1
1=1
true

not extraneous
an extraneous root would be x=-34
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The slope intercept form of a line is

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Step-by-step explanation:

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Step-by-step explanation:

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