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2 years ago

X=y+6 X+6y=20 Solving systems of equations using substitution

1 answer:

8 0

To get the answer we can subsittute first equation into second.
x+6y=20
y+6+6y=20
6+7y=20 /-6
7y=14 /:2
y=2
Now we can back substitute
x=y+6
x=2+6
x=8
Finally we get
x=8
y=2

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M∠LON = 7x-92 and m∠MON = 6x+12

Tomtit [17]

Answer:

$M∠LOM = \boxed{48}$

Step-by-step explanation:

$M∠LOM + m∠MON = 180 \\ 7x-92 + 6x+12 = 180 \\ 13x - 80 = 180 \\ 13x = 180 + 80 \\ 13x = 260 \\ \boxed{ x = 20} \\ (7x - 92 )= 140 - 92 = \boxed{48} \\$

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2 years ago

Will mark branniest if gotten right

iris [78.8K]

Answer:

? = 30°

Step-by-step explanation:

All angles in a triangle add up to 180°

? + 130° + 20° = 180°

? = 180° - 130° - 20°

? = 30°

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2 years ago

Which is more 11 pints or 1 gallon

siniylev [52]

Answer:

11 pints

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3 years ago

Read 2 more answers

Find the distance of the line segment joining the two points (-4 /2 - /12) and (/32, 2/3)

astraxan [27]

Answer: $4\sqrt{3}$ .

Step-by-step explanation:

Distance formula : Distance between points (a,b) and (c,d) is given by :-

$D=\sqrt{(d-b)^2+(b-a)^2}$

Distance between points $(-4\sqrt{2},\sqrt{12}) \text{ and }(-\sqrt{32}, 2\sqrt{3})$ .

$D=\sqrt{(2\sqrt{3}-(-\sqrt{12}))^2+(-\sqrt{32}-(-4\sqrt{2}))}\\\\=\sqrt{(2\sqrt{3}+\sqrt{2\times2\times3})^2+(-\sqrt{4\times4\times2}+4\sqrt{2})^2}\\\\=\sqrt{(2\sqrt{3}-\sqrt{2^2\times3})^2+(-\sqrt{4^2\times2}+4\sqrt{2})^2}\\\\=\sqrt{(2\sqrt{3}+2\sqrt{3})^2+(-4\sqrt{2}+4\sqrt{2})^2}\\\\=\sqrt{(4\sqrt{3})^2+0}\\\\=4\sqrt{3}\text{ units}$

Hence, the correct option is $4\sqrt{3}$ .

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3 years ago

Find p and q for which the linear eqn has infinite solutions

jekas [21]

Answer:

p= 2.5

q= 7

Step-by-step explanation:

The lines should overlap to have infinite solutions, slopes should be same and y-intercepts should be same.

Equations in slope- intercept form:

6x-(2p-3)y-2q-3=0 ⇒ (2p-3)y= 6x -2q-3 ⇒ y= 6/(2p-3)x -(2q+3)/(2p-3)

12x-( 2p-1)y-5q+1=0 ⇒ (2p-1)y= 12x - 5q+1 ⇒ y=12/(2p-1)x - (5q-1)/(2p-1)

Slopes equal:

6/(2p-3)= 12/(2p-1)

6(2p-1)= 12(2p-3)

12p- 6= 24p - 36

12p= 30

p= 30/12

p= 2.5

y-intercepts equal:

(2q+3)/(2p-3)= (5q-1)/(2p-1)

(2q+3)/(2*2.5-3)= (5q-1)/(2*2.5-1)

(2q+3)/2= (5q-1)/4

4(2q+3)= 2(5q-1)

8q+12= 10q- 2

2q= 14

q= 7

7 0

3 years ago