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kirill [66]
4 years ago
9

Peggy had three times as many quarters as nickels. She had $1.60 in all. How many nickels and how many quarters did she have? Wh

ich of the following equations could be used to solve the problem?
Mathematics
1 answer:
svlad2 [7]4 years ago
3 0
Let q and n represent the number of quarters and nickels respectively.

q=3n and .05n+.25q=1.6  These are the conditions in mathematical terms.

To solve, use the value of q from the first equation in the second equation to get:

.05n+.25(3n)=1.6  carry out indicated multiplication on left side

.05n+.75n=1.6  combine like terms on left side

.8n=1.6  divide both sides by .8

n=2, since q=3n

q=6

So Peggy had 2 nickels and 6 quarters.
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If Professor Wilson found that the test scores of his students had a variance of 4.4, what is the standard deviation? Type a num
malfutka [58]

Answer:

The standard deviation will be: 2.1        

Step-by-step explanation:

We know that standard deviation is basically the square root of variance.

Using the formula to calculate the standard deviation

s=\sqrt{s^2}

As

  • The variance =  s² = 4.4

so the standard deviation can be calculated as:

standard deviation =\sqrt{s^2}

                                 =\sqrt{\left(4.4\right)^}

                                  =2.1

Therefore, the standard deviation will be: 2.1                      

8 0
3 years ago
The mean of 67004, 67004, 67005, 67005, 67005, 67005, 67006, 67006
romanna [79]

Answer:

the answer is 59467

<h2><em>hope it will help you</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em></h2>

8 0
3 years ago
Simplify the trigonometric expression sin(4x) +2 sin(2x) using Double-Angle<br> Identities.
emmasim [6.3K]

Answer:

8sin(x)cos³(x)

Step-by-step explanation:

sin(4x) +2 sin(2x)  = 2sin(2x)*cos(2x) + 2sin(2x) = 2sin(2x)(cos2x + 1)=

= 2sin(2x)(cos²x - sin²x + cos²x + sin²x)=²2sin(2x)*(2cos²x)=

= 4*2sin(x)*cos(x)*cos²(x)= 8sin(x)cos³(x)

6 0
3 years ago
In a lottery game, a player picks six numbers from 1 to 27. If the player matches all six numbers, they win 40,000 dollars. Othe
Alexus [3.1K]

Answer:

We conclude that  expected value of this game is -0.865$.

Step-by-step explanation:

We know that in a lottery game, a player picks six numbers from 1 to 27.

We know that

C_6^{27}=296010

As there is only one advantageous combination, we conclude that the number of non-winning combinations is 296009.

He can win 40,000 dollars.

We calculate:

E(X)=\frac{1}{296010}\cdot 40000\$- \frac{296009}{296010}\cdot 1\$\\\\E(X)=\frac{40000-296009}{296010}\, \$\\\\E(X)=-0.865\, \$

We conclude that  expected value of this game is -0.865$.

7 0
3 years ago
In her metalwork class, Anja cut a square of
Paul [167]

Given:

Anju cut square of tin, of edge 3.7 cm, from a larger square of edge 6.3 cm.

To find:

The area of the remaining tin.

Solution:

Area of a square is:

Area=a^2

Where, a is the edge of the square.

Area of the smaller square is:

A_1=(3.7)^2

A_1=13.69

Area of the larger square is:

A_2=(6.3)^2

A_2=39.69

The area of the remaining tin is:

A=A_2-A_1

A=39.69-13.69

A=26

Therefore, the area of the remaining tin is 26 sq. cm.

8 0
3 years ago
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