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stira [4]
3 years ago
12

The Skubic family and the Shaw family went on a safari tour in which they drove their own vehicles through the park to view the

animals. The cost of the tour was $5.25 per vehicle plus an additional amount for each person in the vehicle. The Skubic family had 7 people in their vehicle and paid $22.75.
If the Shaw family had 3 people in their vehicle, how much did they pay?

$2.50$7.50$12.75$17.25
Mathematics
2 answers:
poizon [28]3 years ago
5 0

Answer:

Correct answer is (C) $12.75

Step-by-step explanation:

Cost of the tour = $5.25 + cost per person(Number of persons)

Let the additional amount for each person in the vehicle by x.

There are 7 people in Skubic family.

So, cost for them = 5.25 + 7x

The total amount they paid = $22.75.

Then, for Skubic family, the cost equation is:

5.25 + 7x = 22.75.

7x = 22.75 - 5.25

= 17.5

x = 17.5/7

= 2.5

Now, there are 3 people in Shaw family.

So, cost for them = 5.25 + 3x

But, x = 2.5

Hence, total cost for Shaw family = 5.25 + 3(2.5)

= 12.75

Hence, the correct answer is (C) $12.75.

Ludmilka [50]3 years ago
4 0
The answer is 12.75 hope this helps.
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Step-by-step explanation:

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3 years ago
Carole's car averages 13.2 mi/gal in city driving and 25.3 mi/gal in highway driving. If she drove a total of 396.0 mi on 19 gal
nika2105 [10]

Answer:

7 gallons were used for city driving.

Step-by-step explanation:

I am going to solve this question by a system of equations.

I am going to say that:

x is the number of gallons driven in the city.

y is the number of gallons driven in the highway.

19 gal of gas

This means that x + y = 19

Carole's car averages 13.2 mi/gal in city driving and 25.3 mi/gal in highway driving. If she drove a total of 396.0 mi.

This means that 13.2x + 25.3y = 396

How many of the gallons (to the nearest gallon) were used for city driving?

This is x

From the first equation, i will have

y = 19 - x

Replacing in the second equation

13.2x + 25.3y = 396

13.2x + 25.3(19 - x) = 396

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12.1x = 84.7

x = \frac{84.7}{12.1}

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5 0
3 years ago
April shoots an arrow upward into the air at a speed of 64 feet per second from a platform that is 11 feet high. The height of t
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Answer:

Maximum height of the arrow is 203 feets

Step-by-step explanation:

It is given that,

The height of the arrow as a function of time t is given by :

h(t)=-16t^2+64t+11..........(1)

t is in seconds

We need to find the maximum height of the arrow. For maximum height differentiating equation (1) wrt t as :

\dfrac{dh(t)}{dt}=0

\dfrac{d(-16t^2+64t+11)}{dt}=0

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Put the value of t in equation (1) as :

h(t)=-16(2)^2+64(2)+11

h(t) = 203 feet

So, the maximum height reached by the arrow is 203 feet. Hence, this is the required solution.

8 0
3 years ago
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