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4 years ago

Need help..................

Mathematics

1 answer:

abruzzese [7]4 years ago

3 0

Answer:

(4-7x)(4+7x)

Step-by-step explanation:

This is a difference of squares. (16 is the square of 4, 49x^2 is the square of 7x.)

The formula for difference of squares is a^2 - b^2 = (a-b)(a+b)

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If you are adding (6a – 3) and (-3a + 6), which of the following choices shows like terms correctly grouped? (1 point) TE O (6a

Anna11 [10]

9514 1404 393

Answer:

(a) (6a - 3a) + (-3+6)

Step-by-step explanation:

Assuming "properly grouped" means that parentheses are placed around each group of terms, the appropriate choice is the one that groups 'a' terms and constant terms:

(6a - 3a) + (-3 + 6)

4 0

3 years ago

Please help ASAP thank you

aliya0001 [1]

Answer:

A) a = 25

B) b = 14

Step-by-step explanation:

hopefully this helps :)

8 0

2 years ago

Read 2 more answers

Find the value of x in each case. Give reasons to justify your solutions<br> Q ∈ PR

slavikrds [6]

The exterior angle theorem states that an exterior angle is equal to the sum of its remote interior angles.

With that we know...

m<QRS+m<RSQ=m<SQP

90+34=x+72

124=x+72

x=52 degrees

answer: 52 degrees

7 0

3 years ago

4(5x - 2) = 72<br> What do I do

Pepsi [2]

Answer:

x = 4

Step-by-step explanation:

4(5x - 2) = 72

Do the distributive property

20x - 8 = 72

Then add 8 to both sides to get 20x alone

20x - 8 = 72

+ 8 + 8

20x = 80

Then divide both sides by 20 to get x

$\frac{20x}{20} = \frac{80}{20}$

x = 4

6 0

3 years ago

Students who party before an exam are twice as likely to fail as those who don't party (and presumably study). If 20% of the stu

True [87]

Answer:

The fraction of the students who failed to went partying = $\frac{1}{10}$

Step-by-step explanation:

Let total number of students = 100

No. of students partied are twice the no. of students who not partied.

⇒ No. of students partied = 2 × the no. of students who are not partied

No. of students partied before the exam = 20 % of total students

⇒ No. of students partied before the exam = $\frac{20}{100}$ × 100

⇒ No. of students partied before the exam = 20

No. of students who not partied before the exam = $\frac{20}{2} = 10$

Thus the fraction of the students who failed to went partying = $\frac{10}{100} = \frac{1}{10}$

8 0

3 years ago