Need help..................

The balance on Taylor's credit card is $2000 it has an interest rate of 12.5% she wants to compare the difference between paying

Svetllana [295]

Answer:

so she saved 82 cents in the interest the month after

Step-by-step explanation:

case 1: payment is $75

interest on 2000 = 0.125/12×2000 = $20.83

so the actual repayment on the balance = (75-20.83) = $54.17

therefore,balance =$(2000-54.7)=$1945.83

interest in the next month = $20.27

case 2: payment is $100

interest on 2000 is still $20.83

repayment = $79.73

balance = $1920.27

interest in the next month = 20.01

so she saved 82 cents in the interest the month after

8 0

3 years ago

How do I find the standard deviation?

brilliants [131]

Answer:

Step-by-step explanation:

Work out the Mean,

Then for every number, subtract the Mean and square the result.

Then work out the mean of those squared differences

and then take the square root of that.

6 0

2 years ago

Emilio has 5 bags of birdseed. Each bag has about 28 ounces of birdseed. If he divides the birdseed equally into 3 containers, a

tigry1 [53]

Answer:

46.66 or if rounded 46.7

Step-by-step explanation:

First you want to do 28x5 that would get you 140

Then, you divide 140 by 3. That would get you ur answer, Hope this helped!! :)

3 0

2 years ago

Can someone pls help thanks

kolezko [41]

I think I think that it is 8 hours. Hopefully that helps!

5 0

3 years ago

A manufacturer of potato chips would like to know whether its bag filling machine works correctly at the 420 gram setting. It is

anastassius [24]

Answer:

$t=\frac{424-420}{\frac{26}{\sqrt{61}}}=1.202$

$p_v =2*P(t_{(60)}>1.202)=0.234$

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can conclude that the true mean is NOT different from 420. So the specification is satisfied.

Step-by-step explanation:

Data given and notation

$\bar X=424$ represent the sample mean

$s=26$ represent the sample standard deviation

$n=61$ sample size

$\mu_o =420$ represent the value that we want to test

$\alpha=0.01$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the true mean is different from 420 or not, the system of hypothesis would be:

Null hypothesis: $\mu = 420$

Alternative hypothesis: $\mu \neq 420$

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{424-420}{\frac{26}{\sqrt{61}}}=1.202$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=61-1=60$

Since is a two sided test the p value would be:

$p_v =2*P(t_{(60)}>1.202)=0.234$

Conclusion

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can conclude that the true mean is NOT different from 420. So the specification is satisfied.

4 0

2 years ago