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Montano1993 [528]
3 years ago
7

Karen and Kristen were in a competition to see who could walk the

Mathematics
1 answer:
Gelneren [198K]3 years ago
5 0

Answer:

They each walked the same amount if you plug 7 into each of their expressions

Step-by-step explanation:

Karen walked 3(7) - 4 or 17 miles

Kristen walked 2(7) + 3 or 17 miles

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The right triangle on the right is a scaled
Whitepunk [10]

Answer:

The scale factor is 3.5

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3 years ago
Paul's dog has 6 puppies. Three of them are a mixture of black and white, two are all black, and one is all white. Express as a
Ludmilka [50]

Answer:

Black and white = 3/6

All Black = 2/6

All White = 1/6

Step-by-step explanation:

3 0
3 years ago
The population of a town is 81,712 and declines continuously at a rate of 4.1% each year. What is the approximate population of
Ganezh [65]
Data:

P (Final population) = ?
Po (Initial population) = 81712
r (rate) = 4,1% = 0,041
t (time in years) = 17

P = Po - (Po*r*t)
P = 81712 -(81712*0,014*17)
P = 81712 - 56953.264
P =24758.736
\boxed{P \approx 24759}

Answer:
B) 24759

4 0
3 years ago
A rhombus ABCD has AB = 10 and m∠A = 60°. Find the lengths of the diagonals of ABCD.
melisa1 [442]
Three important properties of the diagonals of a rhombus that we need for this problem are:
1. the diagonals of a rhombus bisect each other
2. the diagonals form two perpendicular lines
3. the diagonals bisect the angles of the rhombus

First, we can let O be the point where the two diagonals intersect (as shown in the attached image). Using the properties listed above, we can conclude that ∠AOB is equal to 90° and ∠BAO = 60/2 = 30°. 

Since a triangle's interior angles have a sum of 180°, then we have ∠ABO = 180 - 90 - 30 = 60°. This shows that the ΔAOB is a 30-60-90 triangle.

For a 30-60-90 triangle, the ratio of the sides facing the corresponding anges is 1:√3:2. So, since we know that AB = 10, we can compute for the rest of the sides.

\overline{OB}:\overline{AB} = 1:2
\overline {OB}:10 = 1:2
\overline{OB} = \frac{1}{2}(10) = 5

Similarly, we have

\overline{AO}:\overline{AB} = \sqrt{3}:2
\overline {AO}:10 = \sqrt{3}:2
\overline{AO} = \frac{\sqrt{3}}{2}(10) = 5\sqrt{3}

Now, to find the lengths of the diagonals, 

\overline{AD} = 2(\overline{AO}) = 10\sqrt{3}
\overline{BC} = 2(\overline{OB}) = 10

So, the lengths of the diagonals are 10 and 10√3.

Answer: 10 and 10√3 units

8 0
3 years ago
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I need help to and no one gives me help sjsjsj
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