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2 years ago

Karen and Kristen were in a competition to see who could walk the

Mathematics

1 answer:

Gelneren [198K]2 years ago

5 0

Answer:

They each walked the same amount if you plug 7 into each of their expressions

Step-by-step explanation:

Karen walked 3(7) - 4 or 17 miles

Kristen walked 2(7) + 3 or 17 miles

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Its all one big question

Verdich [7]

Answer:

see explanation

Step-by-step explanation:

h(x) + k(x) = x² + 1 + x - 2 = x² + x - 1

(h + k)(2) = 2² + 2 - 1 = 4 + 2 - 1 = 5

h(x) - k(x) = x² + 1 - (x - 2) = x² + 1 - x + 2 = x² -x + 3

(h - k)(3) = 3² - 3 + 3 = 9 - 3 + 3 = 9

h(2) = 2² + 1 = 4 + 1 = 5

k(3) = 3 - 2 = 1

3h(2) + 2k(3) = (3 × 5) + (2 × 1) = 15 + 2 = 17

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2 years ago

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The slope of the line tangent to the curve y^2 + (xy+1)^3 = 0 at (2, -1) is ...?

Lina20 [59]

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\\\frac{dy}{dx}2y + \left(\frac{d}{dx}(xy)+\frac{d}{dx}1\right)\ * 3(xy+1)^2 = 0
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\\\frac{dy}{dx}2y + \left(\frac{dx}{dx}y+x\frac{dy}{dx}+\frac{dx}{dx}0\right)\ * 3(xy+1)^2 = 0
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\\\frac{dy}{dx}2y + \left(y+x\frac{dy}{dx}\right)\ * 3(xy+1)^2 = 0$
$\frac{dy}{dx}2y + \left(y+x\frac{dy}{dx}\right)\ * 3(xy+1)^2 = 0
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\\2y\ y' + \left(3y+3x\ y'\right) (xy+1)^2 = 0
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\\2y\ y' + \left(3y+3x\ y'\right) ((xy)^2+2xy+1) = 0
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\\2y\ y' + \left(3y+3x\ y'\right) ((xy)^2+2xy+1) = 0
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\\2y\ y' + 3x^2y^3 +6xy^2+3y+(3x y' +6x^2y y'+3x^2y y') = 0
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\\3x^2y^3 +6xy^2+3y+(3x y' +6x^2y y'+3x^2y y'+2yy' ) = 0
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\\y'(3x +6x^2y+3x^2y+2y ) = -3x^2y^3 -6xy^2-3y

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$y' = \frac{-3x^2y^3 -6xy^2-3y}{(3x +6x^2y+3x^2y+2y )};\ x=2,y=-1
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2 years ago

Mike and his dad are retiling his bathroom floor. They have budgeted $200 for the tiles and supplies. The tiles cost $1.85 each

Feliz [49]

Answer:

Equation: $114.90 + $1.85<em>x</em> = 200

Solution: They can buy 46 tiles.

Step-by-step explanation:

First, subtract 114.90 from both sides to get 1.85<em>x</em> = 85.10.

Divide 85.10 by 1.85 to get 46, which is the answer.

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2 years ago

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Alex787 [66]

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2 years ago

A sphere has a radius of 6 meters. A second sphere has a radius of 3 meters. What is the difference of the volumes of the sphere

cricket20 [7]

∆volume = 4/3 *pi * (R^3 -r^3 )
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2 years ago

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