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3 years ago

Please help me?

Mathematics

2 answers:

lys-0071 [83]3 years ago

4 0

<span>B. -6y = 12 is the asnwer</span>

ANEK [815]3 years ago

3 0

Your answer would be B

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Hello! i need help! I Am a 5th grade scholar

stich3 [128]

0.4 is 10 times as much as 0.04

this is because 0.04 times 10 is 0.4

0.003 is 1/10 of 0.03

0.003 times 10 is 0.03

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3 years ago

Jim is able to sell a hand-carved statue for $670 which was a 35% profit over his cost. How much did the statue originally cost

n200080 [17]

A)496.30, hope this helped

7 0

3 years ago

A mass of 5 kg stretches a spring 10 cm. The mass is acted on by an external force of 10sin( t ) N(newtons) and moves in a mediu

yKpoI14uk [10]

Answer:

A) C1 = 0.00187 m = 0.187 cm, C2 = 0.0062 m = 0.62 cm

B) A sample of how the graph looks like is attached below ( periodic sine wave )

C) w = $\sqrt[4]{3}$ is when the amplitude of the forced response is maximum

Step-by-step explanation:

Given data :

mass = 5kg

length of spring = 10 cm = 0.1 m

f(t) = 10sin(t) N

viscous force = 2 N

speed of mass = 4 cm/s = 0.04 m/s

initial velocity = 3 cm/s = 0.03 m/s

Formulating initial value problem

y = viscous force / speed = 2 N / 0.04 m/s = 50 N sec/m

spring constant = mg/ Length of spring = (5 * 9.8) / 0.1 = 490 N/m

f(t) = 10sin(t/2) N

using the initial conditions of u(0) = 0 m and u"(0) = 0.03 m/s to express the equation of motion

the equation of motion = 5u" + 50u' + 490u = 10sin(t/2)

A) finding the solution of the initial value

attached below is the solution and

B) attached is a periodic sine wave replica of how the grapgh of the steady state solution looks like

C attached below

3 0

3 years ago

WILL MARK BRAINLIEST!

Artist 52 [7]

Answer:

Following are the responses to the given points:

Step-by-step explanation:

Dilation implies the triangle $\Delta XYZ$ stretched through the factor "2".

$m\angle Y = m\angle C = 90^{\circ} \leftarrow given \\\\$

right triangles:

$\Delta XYZ and \Delta ACB \\\\\angle X \cong \angle A \leftarrow given\\\\$

complementary angles:

$\angle X \ and\ \angle Z$

$m\angle Z = 90^{\circ} - m\angle X \\\\$

complementary angles:

$\angle A \ and\ \angle B$

$m\angle B = 90^{\circ} - m\angle A \\\\\therefore \\\\ \angle Z \cong \angle B \\\\\Delta XYZ \sim \Delta ACB \\\\$

Same triangles: proportional side are corresponding, congruence angles are respective.

$\sin \angle X = \frac{5}{5.59} \leftarrow given \\\\\sin\angle X = \frac{YZ}{XY} \\\\YZ = 5 (units) \rightarrow leg in \Delta XYZ \\\\XZ = 5.59 (units) \rightarrow hypotenuse \ in\ \Delta XYZ\\\\$

Calculating the length of leg XY:

$XY = \sqrt{((5.59)^2 - 52)} \cong 2.4996 (units)\\\\\frac{CB}{YZ} = 2 \leftarrow given \\\\CD = 2YZ = 2 \times 5 = 10 \ (units)\\\\\frac{AC}{XY} = 2 \leftarrow \ given\\\\AC = 2XY \cong 2 \times 2.4996 \cong 4.999\ (units)\\\\$

3 0

2 years ago

Help, please I would appreciate it.

Veronika [31]

At firt we should solve what is h(0)
h(0)=0^2+2
h(0)=2
So then you should take the h(0) answer to g(x) and the result is g(2)= -2-5=-7

3 0

2 years ago