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3 years ago

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A region is bounded by semicircular arcs constructed on the side of a square whose sides measure 2/\pi, as shown. What is the pe

rimeter of this region?

1 answer:

Paladinen [302]3 years ago

4 0

Answer:

4

Step-by-step explanation:

The perimeter of the region is equal to the sum of the perimeter of the four semicircular arc. Since the semicircular arcs have the same measure, therefore:

Perimeter of region = 4 × Perimeter of semicircular arc.

The side of the square = diameter of the semicircle = 2/π.

The radius of semicircle = diameter/2 = $\frac{2/\pi}{2} =\frac{1}{\pi}$

The perimeter of a semicircle = perimeter of a circle ÷ 2

$Perimeter\ of \ semicircle = \frac{perimeter\ of\ circle}{2}=\frac{2\pi r}{2}=\frac{2\pi (\frac{1}{\pi} )}{2} =1\\ Perimeter\ of\ region = 4*Perimeter\ of \ semicircle=4*1=4\$

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Answer:

38.70 miles

Step-by-step explanation:

Each week, Reuben jogs ...

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Then in 2 weeks, he jogs ...

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3 years ago

The one-time fling! Have you ever purchased an article of clothing (dress, sports jacket, etc.), worn the item once to a party,

Mama L [17]

Answer:

$(a)\ P(x = 0) = 0.2725$

$(b)\ P(x \ge 1) =0.7275$

$(c)\ P(x \le 2) = 0.8948$

Step-by-step explanation:

Given

$n = 8$ --- 8 friends

$p = 15\%$ --- proportion that one-time fling

This question is an illustration of binomial probability, and it is represented as:

$P(X = x) = ^nC_x* p^x * (1 - p)^{n-x}$

Solving (a): P(x = 0) --- None has done one time fling

$P(x = 0) = ^8C_0* (15\%)^0 * (1 - 15\%)^{8-0}$

$P(x = 0) = 1* 1 * (1 - 0.15)^{8}$

$P(x = 0) = 0.85^8$

$P(x = 0) = 0.2725$

Solving (b): $P(x \ge 1)$

To do this, we make use of compliment rule:

$P(x = 0) + P(x \ge 1) =1$

Rewrite as:

$P(x \ge 1) =1 - P(x = 0)$

$P(x \ge 1) =1 - 0.2725$

$P(x \ge 1) =0.7275$

Solving (c): $P(x\le 2)$ --- Not more than 2 has one time fling

This is calculated as:

$P(x\le 2) = P(x = 0) + P(x =1) + P(x = 2)$

We have:

$P(x = 0) = 0.2725$

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$P(x = 1) = 8* (0.15) * (1 - 0.15)^7$

$P(x = 1) = 0.3847$

$P(x = 2) = ^8C_2* (15\%)^2 * (1 - 15\%)^{8-2}$

$P(x = 2) = 28* (0.15)^2 * (1-0.15)^6$

$P(x = 2) = 0.2376$

So:

$P(x\le 2) = P(x = 0) + P(x =1) + P(x = 2)$

$P(x \le 2) = 0.2725 + 0.3847 + 0.2376$

$P(x \le 2) = 0.8948$

4 0

3 years ago

Please answer quickly:

mina [271]

You have to move variables on one side and constants on the other aby - b + b = c + b aby = c + b y = (c + b)/ab

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3 years ago

Read 2 more answers