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3 years ago

A gardening company plants 10 trees in 2 hours.

Mathematics

2 answers:

almond37 [142]3 years ago

7 0

20 hours just x the two numbers

o-na [289]3 years ago

4 0

Well what I would do is how much do I have to multiply by to get 150 trees which is 1.5. So now we take the 1.5 and the 2 hour multiply them and now we have 3. 3 hours is your answer

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1. A hotel manager buys 30 pillow cases and 25 shower curtains for $375. The manager then buys another 28 pillow cases and 35 sh

skad [1K]

Answer:

For #2: It's C. 17 nickels and 15 quarters.

Step-by-step explanation:

17*5= 85

15*25= 375

375+85= 460

add in the decimal:

17* 5 cents= $.85

15* 25 cents= $3.75

$3.75+ $.85= $4.60

7 0

3 years ago

Brittany will be working full time this summer to save for her goal of having 10,000 by the time she is 21. Brittany has an acco

photoshop1234 [79]

Answer:

$ 8,695.35

Step-by-step explanation:

This is a compound interest question

Amount after t years = A = P(1 + r/n)^nt

Where P = Initial Amount saved

r = interest rate

t = time in years

n = compounding frequency

A = 10,000

r = 3.5 %

t = 21 - 17 = 4 years

n = Compounded monthly = 12

Step 1

Converting R percent to r a decimal

r = R/100 = 3.5%/100 = 0.035 per year.

P = A / (1 + r/n)^nt

Solving our equation:

P = 10000 / ( 1 + (0.035/12)^12 ×4 =

P = $8,695.35

The principal investment required to get a total amount, principal plus interest, of $10,000.00 from interest compounded monthly at a rate of 3.5% per year for 4 years is $8,695.35.

8 0

3 years ago

Solve the system of equations. 3x – 7y = 5 9y = 5x + 5

Ulleksa [173]

The answer X= -10 y= -5
Hope this is helpful

3 0

2 years ago

Worth 10 pts ... pls help

Wewaii [24]

Answer:

the length is 8cm???

Step-by-step explanation:

its kind of obvi (i Think)

6 0

3 years ago

Read 2 more answers

What’s the domain and range of: log(√(2x-1) + 3 ) Please explain how you got it too!!

Radda [10]

Two main facts are needed here:

1. The logarithm $\log x$ , regardless of the base of the logarithm, exists for $x>0$ .

2. The square root $\sqrt x$ exists for $x\ge0$ .

(in both cases we're assuming real-valued functions only)

By (2) we know that $\sqrt{2x-1}$ exists if $2x-1\ge0$ , or $x\ge\dfrac12$ .

By (1), we know that $\log(\sqrt{2x-1}+3)$ exists if $\sqrt{2x-1}+3>0$ , or $\sqrt{2x-1}>-3$ . But as long as the square root exists, it will always be positive, so this condition will always be met.

Ultimately, then, we only require $x\ge\dfrac12$ , so the function has domain $\left[\dfrac12,\infty)$ .

To determine the range, we need to know that, in their respective domains, $\sqrt x$ and $\log x$ increase monotonically without bound. We also know that $x=\dfrac12$ at minimum, at which point the square root term vanishes, so the least value the function takes on is $\log3$ . Then its range would be $[\log3,\infty)$ .

3 0

3 years ago