![\bf \lim\limits_{x\to \infty}~\left( \cfrac{1}{8} \right)^x\implies \lim\limits_{x\to \infty}~\cfrac{1^x}{8^x}\\\\[-0.35em] ~\dotfill\\\\ \stackrel{x = 10}{\cfrac{1^{10}}{8^{10}}}\implies \cfrac{1}{8^{10}}~~,~~ \stackrel{x = 1000}{\cfrac{1^{1000}}{8^{1000}}}\implies \cfrac{1}{8^{1000}}~~,~~ \stackrel{x = 100000000}{\cfrac{1^{100000000}}{8^{100000000}}}\implies \cfrac{1}{8^{100000000}}~~,~~ ...](https://tex.z-dn.net/?f=%5Cbf%20%5Clim%5Climits_%7Bx%5Cto%20%5Cinfty%7D~%5Cleft%28%20%5Ccfrac%7B1%7D%7B8%7D%20%5Cright%29%5Ex%5Cimplies%20%5Clim%5Climits_%7Bx%5Cto%20%5Cinfty%7D~%5Ccfrac%7B1%5Ex%7D%7B8%5Ex%7D%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7Bx%20%3D%2010%7D%7B%5Ccfrac%7B1%5E%7B10%7D%7D%7B8%5E%7B10%7D%7D%7D%5Cimplies%20%5Ccfrac%7B1%7D%7B8%5E%7B10%7D%7D~~%2C~~%20%5Cstackrel%7Bx%20%3D%201000%7D%7B%5Ccfrac%7B1%5E%7B1000%7D%7D%7B8%5E%7B1000%7D%7D%7D%5Cimplies%20%5Ccfrac%7B1%7D%7B8%5E%7B1000%7D%7D~~%2C~~%20%5Cstackrel%7Bx%20%3D%20100000000%7D%7B%5Ccfrac%7B1%5E%7B100000000%7D%7D%7B8%5E%7B100000000%7D%7D%7D%5Cimplies%20%5Ccfrac%7B1%7D%7B8%5E%7B100000000%7D%7D~~%2C~~%20...)
now, if we look at the values as "x" races fast towards ∞, we can as you see above, use the values of 10, 1000, 100000000 and so on, as the value above oddly enough remains at 1, it could have been smaller but it's constantly 1 in this case, the value at the bottom is ever becoming a larger and larger denominator.
let's recall that the larger the denominator, the smaller the fraction, so the expression is ever going towards a tiny and tinier and really tinier fraction, a fraction that is ever approaching 0.
Answer:
k - 3 : k + 2
Step-by-step explanation:
3 less than k = k - 3
2 more than k = k + 2
Ratio of 3 less than k to 2 more than k
In ratios, the word 'to' is represented as a colon :
k - 3 : k + 2
Hope this helps :)
2 2/3
Step-by-step explanation:
multiply eight times one
it will be eight over three
the divide eight by three and put in a mixed number
Answer:
-4
Step-by-step explanation:
Find the gradient of the line segment between the points (0,2) and (-2,10).
Given data
x1= 0
x2= -2
y1= 2
y2=10
The expression for the gradient is given as
M= y2-y1/x2-x1
substitute
M= 10-2/-2-0
M= 8/-2
m= -4
Hence the gradient is -4
"1 x 1" means whatever you want it to mean. There is nothing that says the operation "x" should be multiplication. There is nothing that says that "1" should even be a number. I could, just to be a regular A-hole, say that "1" is shorthand for a set of elements, and "x" is just a nice way of pairing "1" with itself, and I can call this a domain for a function I am about to define.
However, if we are being totally serious here, "x" means the operation of multiplication and "1" is a commonly understood concept referring to the idea of a single thing by itself. Multiplication is a short-cut for lengthy addition problems.
So 3x4 is a short cut for 3 + 3 + 3 + 3, or equivalently, 4 + 4 + 4. That's pretty much it. How many times do I add up 3? How many times to I add up 4?
So when you ask what is "1 x 1", you are really asking How many times do I add up 1? Well, you add up 1 just 1 time. That gives you 1.
