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3 years ago

If a salon charges rupees 99 for a haircut, how much money did the salon earn over the week?

Mathematics

2 answers:

gayaneshka [121]3 years ago

7 0

Answer:

$\text{(b) }$ ₹ $5,940$

Step-by-step explanation:

Each pair of scissors on the chart represents 5 haircuts, as indicated by the key. There are 2 scissors on Saturday and 10 scissors on Sunday, hence a total of 12 scissors over the weekend. Therefore, there were $12\cdot 5=60$ haircuts over the weekend.

Since the salon charges 99 rupees per cut, they made a total of $99\cdot 60=\boxed{5,940}$ rupees over the weekend.

Alexxandr [17]3 years ago

4 0

Answer:

5940 rupees

Step-by-step explanation:

99 multiplied by 29×5 is 5940

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In a right triangle ABC, angle C is a right angle and cos B =255/257.

butalik [34]

Answer:

Step-by-step explanation:

Given

cosB = $\frac{adjacent}{hypotenuse}$ = $\frac{BC}{A B}$ = $\frac{255}{257}$

Then the hypotenuse AB = 257 and BC = 255

sinA = $\frac{opposite}{hypotenuse}$ = $\frac{BC}{AB}$ = $\frac{255}{257}$

A = $sin^{-1}$ ( $\frac{255}{257}$ ) = 82.8° → C

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4 years ago

18.<br> What is the value of the function f(x)--x-3 when x = 12?<br> Answer

egoroff_w [7]

Answer:

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4 years ago

HELP ME WITH THIS GEOMETRY QUESTION!!! 18 POINTS!

ikadub [295]

Answer:

120

Step-by-step explanation:

The arcs are in the ratio:

3 : 3 : 4 : 5

Add all numbers in the ratio:

3 + 3 + 4 + 5 = 15

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360/15 = 24

Multiply all numbers in the ratio by 24.

72 : 72 : 96 : 120

Answer:

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3 0

3 years ago

(At6) √2<br>Solve the equation

Sergeu [11.5K]

Answer:

${at}^{6} \sqrt{2}$

Step-by-step explanation:

1) Remove the parentheses.

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5 0

3 years ago

Match the function in the left column with its period in the right column.

kiruha [24]

The results for the matching between function and its period are:

Option 1 - Letter D
Option 2 - Letter A
Option 3 - Letter C
Option 4 - Letter B

<h3>What is a Period of a Function?</h3>

If a given function presents repetitions, you can define the period as the smallest part of this repetition. As an example of periodic functions, you have: sin(x) and cos(x).

$\mathrm{Period\:of\:}a\cdot \cos \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\cos \left(x\right)}{|b|}$

$\mathrm{Period\:of\:}a\cdot \sin \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\sin \left(x\right)}{|b|}$

The period of sin(x) and cos(x) is 2π.

For solving this question, you should analyze each option to find its period.

1) Option 1

$\mathrm{Periodicity\:of\:}a\cdot \cos \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\cos \left(x\right)}{|b|}\\ \\ \mathrm{Periodicity\:of\:}a\cdot \cos \left(bx\:+\:c\right)\:+\:d=\frac{2\pi }{\frac{1}{2} }=4\pi$

Thus, the option 1 matches with the letter D.

2) Option 2

$\mathrm{Period\:of\:}a\cdot \sin \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\sin \left(x\right)}{|b|}\\ \\ \mathrm{Period\:of\:}a\cdot \sin \left(bx\:+\:c\right)\:+\:d=\frac{2\pi}{4} =\frac{\pi }{2}$

Thus, the option 2 matches with the letter A.

3) Option 3

Thus, the option 3 matches with the letter C.

4) Option 4

Thus, the option 4 matches with the letter B.

Read more about the period of a trigonometric function here:

brainly.com/question/9718162

#SPJ1

6 0

2 years ago