The median ( Q2 ) divides the data set into two parts, the upper set and the lower set. The lower quartile ( Q1 ) is the median of the lower half, and the upper quartile ( Q3 ) is the median of the upper half. Example: Find Q1 , Q2 , and Q3 for the following data set, and draw a box-and-whisker plot.

6 0

3 years ago

Evaluate 16^1/2 x 2^-3<br> Give your answer as a fraction in its simplest form.

kati45 [8]

Your answer would be 1/2

6 0

3 years ago

27=3 raised to power (2x_1)

Ivahew [28]

Answer:

x = 2

Step-by-step explanation:

$27=3^{2x-1}\\\\3^{3}=3^{2x-1}\\$

Bases are equal. So, compare powers

2x - 1 = 3

Add 1 to both sides,

2x = 3+1

2x = 4

Divide both sides by 2

x = 4/2

x = 2

7 0

2 years ago

Help with this question Asap!! I need all the help I can get!

tankabanditka [31]

Answer:

$\large{YES}\ \dfrac{BC}{YZ}=\dfrac{AC}{XY}=\dfrac{AB}{XZ}=\dfrac{2}{1}\\\\\text{and}\ \angle B\cong\angle Z,\ \angle C\cong\angle Y,\ \angle A\cong\angle X$

Step-by-step explanation:

$BC\to ZY\\AB\to XZ\\AC\to XY\\\angle A\to\angle X\\\angle B\to\angle Z\\\angle C\to\angle Y$

$\text{We have:}\\\\\triangle ABC:\ AB=20,\ BC=12,\ AC=18\\\triangle XZY:\ XZ=10,\ YZ=6,\ XY=9\\\\\text{check the ratio:}\\\\\dfrac{AB}{XZ}=\dfrac{20}{10}=2\\\\\dfrac{BC}{YZ}=\dfrac{12}{6}=2\\\\\dfrac{AC}{XY}=\dfrac{18}{9}=2\\\\\text{CORRECT :)}\\\\\angle B\cong\angle Z,\ \angle C\cong\angle Y\\\\\text{We know that: The sum of the acute angles in a right triangle is}\ 90^o.\\\\m\angle B+m\angle A=90^o\ \text{and}\ m\angle Z+m\angle X=90^o$

$\text{We know}\ m\angle B=m\angle Z\to \ m\angle A=m\angle X.\\\text{therefore}\ \angle A\cong\angle X$

5 0

3 years ago