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denis-greek [22]
2 years ago
11

What is the factored form of x2 – 6x – 16?

Mathematics
2 answers:
Alisiya [41]2 years ago
5 0
( x - 8 ) ( x + 2 ) hope this helped
inna [77]2 years ago
4 0
It should be

(x-8)(x+2)
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Ms. Knight's two cooking classes are
Radda [10]

Answer:

20

Step-by-step explanation:

In class 1, they used 10 sweet potatoes.

If they need 30, in class 2, they used 20.

5 0
3 years ago
For most answers, you will simply enter your numeric answer directly into the space provided to the right of the equal sign. Ans
Vedmedyk [2.9K]

Answer:

12 dozens of eggs I believe

Step-by-step explanation:

12 eggs are in one dozen

<em>Divide</em><em> </em><em>1</em><em>4</em><em>4</em><em> </em><em>by</em><em> </em><em>1</em><em>2</em><em>. </em><em> </em><u>1</u><u>4</u><u>4</u><u>÷</u><u>1</u><u>2</u><u>=</u><u>1</u><u>2</u>

4 0
3 years ago
Ginny is studying a population of frogs. She determines that the population is decreasing at an average rate of 3% per year. Whe
Rama09 [41]

You can see how this works by thinking through what's going on.

 

In the first year the population declines by 3%.  So the population at the end of the first year is the starting population (1200) minus the decline: 1200 minus 3% of 1200.  3% of 1200 is the same as .03 * 1200.  So the population at the end of the first year is 1200 - .03 * 1200.  That can be written as 1200 * (1 - .03), or 1200 * 0.97

 

What about the second year?  The population starts at 1200 * 0.97.  It declines by 3% again.  But 3% of what???  The decline is based on the population at the beginning of the year, NOT based no the original population.  So the decline in the second year is 0.03 * (1200 * 0.97).  And just as in the first year, the population at the end of the second year is the population at the beginning of the second year minus the decline in the second year.  So that's 1200 * 0.97 - 0.03 * (1200 * 0.97), which is equal to 1200 * 0.97 (1 - 0.03) = 1200 * 0.97 * 0.97 = 1200 * 0.972.

 

So there's a pattern.  If you worked out the third year, you'd see that the population ends up as 1200 * 0.973, and it would keep going like that.

 

So the population after x years is 1200 * 0.97x

5 0
3 years ago
Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse
Drupady [299]

Answer:

a'(d) = \frac{d}{5} + \frac{3}{5}

a(a'(d)) = a'(a(d)) = d

Step-by-step explanation:

Given

a(d) = 5d - 3

Solving (a): Write as inverse function

a(d) = 5d - 3

Represent a(d) as y

y = 5d - 3

Swap positions of d and y

d = 5y - 3

Make y the subject

5y = d + 3

y = \frac{d}{5} + \frac{3}{5}

Replace y with a'(d)

a'(d) = \frac{d}{5} + \frac{3}{5}

Prove that a(d) and a'(d) are inverse functions

a'(d) = \frac{d}{5} + \frac{3}{5} and a(d) = 5d - 3

To do this, we prove that:

a(a'(d)) = a'(a(d)) = d

Solving for a(a'(d))

a(a'(d))  = a(\frac{d}{5} + \frac{3}{5})

Substitute \frac{d}{5} + \frac{3}{5} for d in  a(d) = 5d - 3

a(a'(d))  = 5(\frac{d}{5} + \frac{3}{5}) - 3

a(a'(d))  = \frac{5d}{5} + \frac{15}{5} - 3

a(a'(d))  = d + 3 - 3

a(a'(d))  = d

Solving for: a'(a(d))

a'(a(d)) = a'(5d - 3)

Substitute 5d - 3 for d in a'(d) = \frac{d}{5} + \frac{3}{5}

a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}

Add fractions

a'(a(d)) = \frac{5d - 3+3}{5}

a'(a(d)) = \frac{5d}{5}

a'(a(d)) = d

Hence:

a(a'(d)) = a'(a(d)) = d

7 0
2 years ago
When two lines intersect to form a 90 degree angle, these lines are called ________ lines?
zalisa [80]
When two lines intersect to form a 90 degree angle, these lines are called perpendicular lines.
5 0
3 years ago
Read 2 more answers
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