How can I use distribution property to multiply a 2 digit number by a 1 digit number?

1 answer:

3 0

You can grab the number form the tens place and add a 0 behind it at the end then multiply by the one digit number. Then you can grab the number from the ones place and multiply it by the one digit number. Finally you would add the both numbers that you multiplied and you would get your answer.

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Which number is farthest from 1 on the number line?

Marrrta [24]

The answer is 1.5

1.2=1.0
1.3=1.1
1.4=1.2
1.5=1.2

7 0

3 years ago

Read 2 more answers

Don't know what to do :\\

____ [38]

Answer: Choice A) 12x^2 - 48x + 21; all real numbers

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Work Shown:

(f * g)(x) = f(x) * g(x)
(f * g)(x) = ( f(x) ) * ( g(x) )
(f * g)(x) = ( -2x+7 ) * ( -6x+3 )
(f * g)(x) = -2x*( -6x+3 ) + 7*( -6x+3 )
(f * g)(x) = -2x*(-6x) - 2x*(3) + 7*(-6x) + 7*(3)
(f * g)(x) = 12x^2 - 6x - 42x + 21
(f * g)(x) = 12x^2 - 48x + 21

The domain is the set of all real numbers because we can plug in any number in for x, to get some output for y. There are no issues to worry about such as division by zero errors, square root of a negative number, etc.

6 0

3 years ago

5.(A.3A) The table represents some points on the graph

Lilit [14]

Answer:

Step-by-step explanation:

7 0

3 years ago

Find sin(a+b) if tan(a)=7/24 where a is in the third quadrant

ludmilkaskok [199]

The complete question in the attached figure

we have that
tan a=7/24 a----> III quadrant
cos b=-12/13 b----> II quadrant
sin (a+b)=?

we know that
sin(a + b) = sin(a)cos(b) + cos(a)sin(b<span>)
</span>
step 1
find sin b
sin²b+cos²b=1------> sin²b=1-cos²b----> 1-(144/169)---> 25/169
sin b=5/13------> is positive because b belong to the II quadrant

step 2
Find sin a and cos a
tan a=7/24
tan a=sin a /cos a-------> sin a=tan a*cos a-----> sin a=(7/24)*cos a
sin a=(7/24)*cos a------> sin²a=(49/576)*cos²a-----> equation 1
sin²a=1-cos²a------> equation 2
equals 1 and 2
(49/576)*cos²a=1-cos²a---> cos²a*[1+(49/576)]=1----> cos²a*[625/576]=1
cos²a=576/625------> cos a=-24/25----> is negative because a belong to III quadrant
cos a=-24/25
sin²a=1-cos²a-----> 1-(576/625)----> sin²a=49/625
sin a=-7/25-----> is negative because a belong to III quadrant

step 3
find sin (a+b)
sin(a + b) = sin(a)cos(b) + cos(a)sin(b)
sin a=-7/25
cos a=-24/25
sin b=5/13
cos b=-12/13
so
sin (a+b)=[-7/25]*[-12/13]+[-24/25]*[5/13]----> [84/325]+[-120/325]
sin (a+b)=-36/325

the answer is
sin (a+b)=-36/325

8 0

3 years ago

A rocket travels in a trajectory given by the equation s = -4.9t 2 + v0t, where s is meters above ground, t is time in seconds a

Reptile [31]

Step-by-step explanation:

s = -4.9t² + 49t

The vertex of the parabola is at t = -b/(2a).

t = -49 / (2 × -4.9)

t = 5

The rocket reaches its maximum height after 5 seconds.

5 0

3 years ago