Y2 - y1/x2 - x1 = slope
4 - 8/ 9 - 5 = slope
-4/4 = slope
-1 = slope
hope this helps :)
Answer:
The probability is 
Step-by-step explanation:
If she has n distinct password candidates and only one of which will successfully log her into a secure system, the probability that her first first successful login will be on her k-th try is:
If k=1

Because, in her first try she has n possibles options and just one give her a successful login.
If k=2

Because, in her first try she has n possibles options and n-1 that are not correct, then, she has n-1 possibles options and 1 of that give her a successful login.
If k=3

Because, in her first try she has n possibles options and n-1 that are not correct, then, she has n-1 possibles options and n-2 that are not correct and after that, she has n-2 possibles options and 1 give her a successful login.
Finally, no matter what is the value of k, the probability that her first successful login will be (exactly) on her k-th try is 1/n
Answer:
the answer is 12
Step-by-step explanation:
p(n)= 6-2(1+n)
so if p(2)
then n=2
therefore,
p(2)= 6-2(1+2)
= 4×3
=12
I know its a long problem but i have to shiw how i got my answer.