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bearhunter [10]

4 years ago

15

On a coordinate plane, a trapezoid is inside of a rectangle to form 3 triangles within the rectangle. The trapezoid has points (

4, 4), (4, 14), (12, 20), and (20, 16). The rectangle has points (4, 4), (4, 20), (20, 20), and (20, 4). Triangle 1 has points (4, 14), (4, 20), (12, 20). Triangle 2 has points (12, 20), (20, 20), (20, 16). Triangle 3 has points (4, 4), (20, 16), (20, 4).
Complete the steps to find the area of the trapezoid.

Area of rectangle = square units

Area of triangle 1 = square units

Area of triangle 2 = square units

Area of triangle 3 = square units

Area of trapezoid = square units

1 answer:

bezimeni [28]4 years ago

5 0

Answer: The correct answers in order are: 256, 24, 16, 96, 120

Explanation:

I completed this assignment

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1) a) $r_{R,I} = 1150\,m$ , b) $r_{R,II} = 3400\,m$ , c) $r_{R,III} = 2750\,m$ .

2) a) $r_{R,I} = 45,2\,km$ , b) $r_{R, II} = 28,15\,km$ , c) $r_{R,III} = 51,8\,km$ .

Explanation:

The scale factor is defined by the following expression:

$n = \frac{r_{S}}{r_{R}}$ (1)

Where:

$n$ - Scale factor.

$r_{S}$ - Scale distance, in centimetres.

$r_{R}$ - Real distance, in centimetres.

1) If we know that $n = \frac{1}{50000}$ , $r_{S,I} = 2,3\,cm$ , $r_{S,II} = 6,8\,cm$ and $r_{S,III} = 5,5\,cm$ , then the actual distances in metres are:

$r_{R,I} = \frac{r_{S,I}}{n}$

$r_{R,I} = \frac{2,3\,cm}{\frac{1}{50000} }$

$r_{R,I} = 115000\,cm$

$r_{R,I} = 1150\,m$

$r_{R,II} = \frac{r_{S,II}}{n}$

$r_{R,II} = \frac{6,8\,cm}{\frac{1}{50000} }$

$r_{R,II} = 340000\,cm$

$r_{R,II} = 3400\,m$

$r_{R, III} = \frac{r_{S, III}}{n}$

$r_{R,III} = \frac{5,5\,cm}{\frac{1}{50000} }$

$r_{R,III} = 275000\,cm$

$r_{R,III} = 2750\,m$

2) If we know that $n = \frac{1}{50000}$ , $r_{S, I} = 90,4\,cm$ , $r_{S, II} = 56,3\,cm$ and $r_{S,III} = 103,6\,cm$ , then the actual distance in kilometres is:

$r_{R,I} = \frac{r_{S,I}}{n}$

$r_{R,I} = \frac{90,4\,cm}{\frac{1}{50000} }$

$r_{R,I} = 4520000\,cm$

$r_{R,I} = 45,2\,km$

$r_{R,II} = \frac{r_{S,II}}{n}$

$r_{R,II} = \frac{56,3\,cm}{\frac{1}{50000} }$

$r_{R,II} = 2815000\,cm$

$r_{R, II} = 28,15\,km$

$r_{R, III} = \frac{r_{S, III}}{n}$

$r_{R,III} = \frac{103,6\,cm}{\frac{1}{50000} }$

$r_{R,III} = 5180000\,cm$

$r_{R,III} = 51,8\,km$

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