Answer:
The 95% CI is (6.93% , 7.47%)
The 99% CI is (6.85% , 7.55%)
Step-by-step explanation:
We have to estimate two confidence intervals (95% and 99%) for the population mean 30-year fixed mortgage rate.
We know that the population standard deviation is 0.7%.
The sample mean is 7.2%. The sample size is n=26.
The z-score for a 95% CI is z=1.96 and for a 99% CI is z=2.58.
The margin of error for a 95% CI is
Then, the upper and lower bounds are:
Then, the 95% CI is
The margin of error for a 99% CI is
Then, the upper and lower bounds are:
Then, the 99% CI is
We are given the following data
n = 35
x = 50
s = 2
CI = 95% (z = 1.96)
The formula for the margin of error is
E = z s / √n
Substituting the given values
E = 1.96 (2) / √35)
E = 0.66 or 66%
Answer:
I would say 85, since 85 would be the median of the three points or 8 hours of studying. I hope this helps! :)
Answer:
=30076 customers
Step-by-step explanation:
Number of customer= 51,200
rate of declination=3.8 %= 0.038
We will use the expresion below in calculating the approximate number of customers that visit the business in 14 years.
A=Pe^(rt)
Where P=initial amt,
r=annual rate of growth or decline,
A=amount after t years.
37800=Pe^.017t
51200=Pe^0.038
P= 51200/e^(0.038*14)
But e^(0.038*14)= 1.7023
P= 51200/1.7023
P=30076
Approximate number of customers that visit the business in 14 years≈30076
Dont say you can't! I believe in youu!