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Leokris [45]
3 years ago
8

A problem states: "There are 2 more horses than cows in a field. There are 16 animals in the field in all. How many horses are t

here in the field?" Let h represent the number of horses. Which equation represents the situation?
Mathematics
2 answers:
Tomtit [17]3 years ago
8 0
The answer is 2h-2. I hope this helps
poizon [28]3 years ago
3 0

Let

h--------> number of horses

c--------> number of cows

we know that

h+c=16 --------> equation 1

h=c+2 --------> equation 2

substitute equation 2 in equation 1

(c+2)+c=16

2c+2=16

2c=16-2

c=7

<u>Find the value of h</u>

h=c+2

h=7+2

h=9

therefore

<u>the answer is</u>

There are 9\ horses and 7\ cows

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Elis [28]

Answer:

The equivalent expression to the givan expression is

\sqrt[4]{324m^{12}}\times\sqrt[3]{64k^9}=12\sqrt[4]{4}m^3k^3

Step-by-step explanation:

Given expression is 4th root of 324m^12 * the cubed root of 64k^9

The given expression can be written as

\sqrt[4]{324m^{12}}\times\sqrt[3]{64k^9}

To find the equivalent expression to the given expression :

\sqrt[4]{324m^{12}}\times\sqrt[3]{64k^9}

=\sqrt[4]{81\times 4m^{12}}\times\sqrt[3]{16\times 4k^9}

=\sqrt[4]{3\times 3\times 3\times 3\times 4m^{12}}\times\sqrt[3]{4\times 4\times 4k^9}

=\sqrt[4]{3\times 3\times 3\times 3\times 4m^{12}}\times\sqrt[3]{4\times 4\times 4k^9}

=(3\times \sqrt[4]{m^{12}})\times (4\times \sqrt[3]{k^9})

=(3\times \sqrt[4]{4m^{12}})\times (4\times \sqrt[3]{k^9})

=(3\times \sqrt[4]{4}\times (m^{12})^{\frac{1}{4}})\times (4\times {(k^9)^{\frac{1}{3}})

=(3\sqrt[4]{4}\times m^{\frac{12}{4}})\times (4\times k^{\frac{9}{3}})

=(3\sqrt[4]{4}\times m^3)\times (4\times k^3)

=3\sqrt[4]{4}m^3.4k^3

=12\sqrt[4]{4}m^3k^3

\sqrt[4]{324m^{12}}\times\sqrt[3]{64k^9}=12\sqrt[4]{4}m^3k^3

Therefore the equivalent expression to the given expression is

\sqrt[4]{324m^{12}}\times\sqrt[3]{64k^9}=12\sqrt[4]{4}m^3k^3

8 0
3 years ago
Determine in which direction the parabola opens y=-3x^2+5x+11<br> up down<br> left <br> right
pav-90 [236]
We have that
y=-3x²<span>+5x+11

we know that
the equation of the parabola in standard form can be expressed in one of the following two ways
y=ax</span>²+bx+c
<span>the parabola opens up if a is positive and opens down if a is negative
and
x=ay</span>²+by+c
the parabola opens right if a is positive and opens left if a is negative
<span>
in this problem 
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</span>y=ax²+bx+c<span>
a=-3
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using a graph tool
see the attached figure
the vertex of a parabola is a maximum

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4 years ago
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3 years ago
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Anon25 [30]

None, the equation 6x - 2 = 6x + 7 does not have any solutions.

<h3>What is an algebraic equation? </h3>

An algebraic equation is an equation that consists of numbers and variables. To solve the variables, there is a need to make use of some or all of the arithmetic operations such as:

  • Addition
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From the given equation:

6x - 2 = 6x + 7

Collect like terms

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0 - 9 = 0

Since there is no variable to solve for in the equation, we can conclude that the equation does not have any solutions.

Learn more about algebraic equations here:

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6 0
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Wittaler [7]

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