What logically could have gone wrong?
1 answer:
The steps to construct a circle circumscribing a triangle are:
- Construct a perpendicular bisector of one side of the triangle
- Construct another perpendicular bisector of another side of the triangle
- The point of intersection of these two perpendicular bisectors is the center
of the circle, we are about to construct.
- Adjust the width of the compass between the intersection point to any of
the corners of the triangle. This width should be the same for all three
vertices
- With the pointer of the compass is located at the intersection point, construct the circle
What could possibly go wrong when the circle only passes two vertices, is the width of the compasses has changed while constructing the circle
Answer: First option
- Construct a perpendicular bisector of one side of the triangle
- Construct another perpendicular bisector of another side of the triangle
- The point of intersection of these two perpendicular bisectors is the center
of the circle, we are about to construct.
- Adjust the width of the compass between the intersection point to any of
the corners of the triangle. This width should be the same for all three
vertices
- With the pointer of the compass is located at the intersection point, construct the circle
What could possibly go wrong when the circle only passes two vertices, is the width of the compasses has changed while constructing the circle
Answer: First option
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Answer:
a. H0 : p ≤ 0.11 Ha : p >0.11 ( one tailed test )
d. z= 1.3322
Step-by-step explanation:
We formulate our hypothesis as
a. H0 : p ≤ 0.11 Ha : p >0.11 ( one tailed test )
According to the given conditions
p`= 31/225= 0.1378
np`= 225 > 5
n q` = n (1-p`) = 225 ( 1- 31/225)= 193.995> 5
p = 0.4 x= 31 and n 225
c. Using the test statistic
z= p`- p / √pq/n
d. Putting the values
z= 0.1378- 0.11/ √0.11*0.89/225
z= 0.1378- 0.11/ √0.0979/225
z= 0.1378- 0.11/ 0.02085
z= 1.3322
at 5% significance level the z- value is ± 1.645 for one tailed test
The calculated value falls in the critical region so we reject our null hypothesis H0 : p ≤ 0.11 and accept Ha : p >0.11 and conclude that the data indicates that the 11% of the world's population is left-handed.
The rejection region is attached.
The P- value is calculated by finding the corresponding value of the probability of z from the z - table and subtracting it from 1.
which appears to be 0.95 and subtracting from 1 gives 0.04998
