To find the distance between any two real numbers, take the greater number (the one lying farthest to the right on a number line) and subtract the lesser number ( the on lying farthest to the left)
Answer:
LHS=(1-sin60)/cos60
=(1-√3÷2)/1÷2
=2(1-√3÷2)
=2-√3
RHS=(1-tan30)/(1+tan30)
={1-(1÷√3)}/{1+(1÷√3)}
={(√3-1)/√3}/{(√3+1)/√3}
=(√3-1)/(√3+1)
={(√3-1)(√3-1)}/{(√3+1)(√3-1)}
=(3-√3-√3+1)/(3-1)
=(4-2√3)/2
=2-√3
Brainliest?
Answer:
The order pair is (2,0)
Step-by-step explanation:
On the picture