Looks to Be answer A have a great day!
1 millimetre = 1/1000 = 1×10^-3 m
Area of a rectangle is length x width.
Let the width = x
The length would be x +7. ( 7 inches longer than the width)
Area = 20
Set up the formula:
20 = x * x+7
Simplify the right side:
20 = x^2 + 7x
Subtract 29 from both sides:
X^2 + 7x -20 = 0
Solve using the quadratic equation
X = -b + sqrt(b^2 -4ac) / 2a
X = -7 + sqrt(7^2-4(1)(-20) / 2(1) (exact answer)
X = 2.178908 ( as a decimal)
The width is 2.178907 inches (round as needed)
The length would be 9.178907 inches ( round as needed.)
Depending on how you round, when you multiply them together you get approximately 20 square inches.
We have that
<span>A' (2,1)
C(-2,2)-------> </span>Using the transformation-----> C' (-2+2,2+1)----> C' (0,3)
with
A' (2,1) and C' (0,3)
find the distance <span>C'A'
d=</span>√[(y2-y1)²+(x2-x1)²]----> d=√[(3-1)²+(0-2)²]----> d=√8----> 2√2 units
the answer is
the distance C'A' is 2√2 units
