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den301095 [7]
3 years ago
10

Is there a rigid transformation that maps triangle ABC to triangle ABD? If so, which transformation?

Mathematics
2 answers:
kow [346]3 years ago
7 0

Answer:

Is there a rigid transformation that maps triangle ABC to triangle ABD? If so, which transformation?

yes, because a translation to the right will map ΔABC to ΔABD

yes, because a rotation about point B will map ΔABC to ΔABD

yes, because a reflection across BA will map ΔABC to ΔABD

no, because no rigid transformation will map ΔABC to ΔABD

Step-by-step explanation:

frutty [35]3 years ago
5 0

Answer: option c

Step-by-step explanation: I took a test

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Write the equation for the line parallel to the given line 4x-3y=9 and through the point (3, -1). Then Write the answers in slop
Katyanochek1 [597]

k:y=m_1x+b_1;\ l:y=m_2x+b_2\\\\k\ \perp\ l\iff m_1\cdot m_2=-1\\\\k\ ||\ l\iff m_1=m_2

We have:

4x-3y=9\ \ \ \ |-4x\\\\-3y=-4x+9\ \ \ \ |:(-3)\\\\y=\dfrac{4}{3}x-3\to m_1=\dfrac{4}{3}

y=m_2x+b\\\\m_2=m_1\to m_2=\dfrac{4}{3}

y=\dfrac{4}{3}x+b

The line passest through the point (3, -1). Substitute the coordinates of the point to the equation of a line:

-1=\dfrac{4}{3}\cdot3+b\\\\-1=4+b\ \ \ \ |-4\\\\b=-5

y=\dfrac{4}{3}x-5\ \ \ \ |\cdot3\\\\3y=4x-15\ \ \ \ |-4x\\\\-4x+3y=-15\ \ \ \ |\cdot(-1)\\\\4x-3y=15

Answer: \boxed{y=\dfrac{4}{3}x-5;\ 4x-3y=15}

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Answer:

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Step-by-step explanation:

Note that this is a decreasing arith. seq.  Each term is smaller than the previous term, the result of the subtraction of 2 1/4 (equivalent to 9/4).  

The fourth term is -11/4; subtracting 9/4 results in -20/4, or -5.

The fifth term is -20/4; subtracting 9/4 results in -29/4.

The 6th term is -29/4; subtracting 9/4 results in -38/4, or -19/2.

The 7th term is -38/4; subtracting 9/4 results in -47/4.

Thus, the "next three terms" following the first four terms are {-29/4, -19/2, -47/4}

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