We have the equation:
We know two points and we will use them to calculate the parameters a and b.
The point (0,3) will let us know a, as b^0=1.
Now, we use the point (2, 108/25) to calcualte b:
![\begin{gathered} y=3\cdot b^x \\ \frac{108}{25}=3\cdot b^2 \\ 3\cdot b^2=\frac{108}{25} \\ b^2=\frac{108}{25\cdot3}=\frac{108}{3}\cdot\frac{1}{25}=\frac{36}{25} \\ b=\sqrt[]{\frac{36}{25}} \\ b=\frac{\sqrt[]{36}}{\sqrt[]{25}} \\ b=\frac{6}{5} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20y%3D3%5Ccdot%20b%5Ex%20%5C%5C%20%5Cfrac%7B108%7D%7B25%7D%3D3%5Ccdot%20b%5E2%20%5C%5C%203%5Ccdot%20b%5E2%3D%5Cfrac%7B108%7D%7B25%7D%20%5C%5C%20b%5E2%3D%5Cfrac%7B108%7D%7B25%5Ccdot3%7D%3D%5Cfrac%7B108%7D%7B3%7D%5Ccdot%5Cfrac%7B1%7D%7B25%7D%3D%5Cfrac%7B36%7D%7B25%7D%20%5C%5C%20b%3D%5Csqrt%5B%5D%7B%5Cfrac%7B36%7D%7B25%7D%7D%20%5C%5C%20b%3D%5Cfrac%7B%5Csqrt%5B%5D%7B36%7D%7D%7B%5Csqrt%5B%5D%7B25%7D%7D%20%5C%5C%20b%3D%5Cfrac%7B6%7D%7B5%7D%20%5Cend%7Bgathered%7D)
Then, we can write the equation as:
Answer:
The total flow in gallons is approximately 16.524 gallons
Step-by-step explanation:
The given diameter of the tank, D = 18 inches
The amount by which the water depth rose, Δh = 15 inches
The quantity being measured = The total flow = The change in volume of water in the tank
The change in the volume of the water in the tank, ΔV = (π × D²/4) × Δh
Substituting the known values, gives;
ΔV = (π × D²/4) × Δh = (π × (18 in.)²/4) × (15 in.) ≈ 3817.035 in.³
1 gallon = 231 in.³
ΔV ≈ 3817.035 in.³ = 3817.035 in.³ × 1 gallon/(231 in.³) ≈ 16.524 gallons
The change in the volume of the water in the tank, ΔV in gallons = The total flow in gallons ≈ 16.524 gallons.
Answer:
27
Step-by-step explanation:
Yes . It happens depending on the numbers!
Answer:
8/10,3/4, -3/4,-7/10
Step-by-step explanation:
From greatest to least, they -7/10 and -3/4 is a negative so thats the least because its below zero. 8/10 and 3/4 is positive so thats a decimal. The greatest is 8/10 because if you divide it, it give you .8 and 3/4 is .75. .8 is greater because it refers to 80 and .80 is greater that .75
