Animals which have the ability to determine the survivability of other
1 answer:
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Answer:
3/16
Explanation:
This cross is a typical dihybrid cross involving two different genes; one coding for seed colour and the other for seed texture in pea plant. The allele for green seeds (Y) is dominant over the allele for yellow seed (y) in the first gene while the allele for round seed (R) is dominant over the allele for wrinkled seed (r) in the second gene.
In a cross between two pea plants heterozygous for both genes i.e. YyRr × YyRr, four possible allelic combinations of gametes will be produced by each parent viz;
YyRr- YR, Yr, yR, yr
Using these gametes in a punnet square (see attached image), 16 possible offsprings will be produced in a phenotypic ratio 9:3:3:1.
Bernard is looking for offsprings with green and wrinkled seeds phenotype. The genotype of this can either be; YYrr or Yyrr. Based on the punnet square, only three (3) offsprings will possess such genotypes, hence, the probability of getting a pea offspring with green and wrinked seed is 3/16.
