Factorise tis please.

(x+3)^{2} +2(x+3)" alt=" (x+3)^{2} +2(x+3)" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

Otrada [13]3 years ago

5 0

$\displaystyle \boxed{(a+b)=a^2+2ab+b^2} \\ \\ (x+3)^2+2(x+3)= \\ x^2+2 \cdot x \cdot 3 +3^2+2x+6 = \\ x^2+6x+9+2x+6= \\ x^2+8x+15= \\ \\ \Delta= b^2-4ac \\ \Delta=8^2-4 \cdot1 \cdot15 \\ \Delta=64-60=4 \\ \\ \\ X_{1,2}= \frac{-b\pm \sqrt{\Delta} }{2a} = \frac{-8\pm2}{2} = \\ \\X1=5 \\ X2=3$

You might be interested in

Solve for x..........

-BARSIC- [3]

9514 1404 393

Answer:

x = -9

Step-by-step explanation:

Segment NL is twice the length of midsegment WV.

2WV = NL

2(x+15) = x+21

2x +30 = x +21 . . . . simplify

x = -9 . . . . . . . . . . . . add -30-x

_____

<em>Additional comment</em>

This value of x means the other segments are ...

MN = 12

WV = 6

NL = 12

5 0

2 years ago

Find the total area the regular pyramid.

Ber [7]

Answer: $14\sqrt{3}$

Step-by-step explanation:

1. You must apply the following formula for calculate the total surface area the regular pyramid:

$SA=\frac{pl}{2}+B$

Where p is the perimeter of the base, l is the slant height and B is the area of the base.

2. The perimeter is, where s is the side length:

$p=3s=3*4=12$

3. The faces are isosceles traingles. So, to find the slant height you can divide one base into two equal right triangles and calculate the slant height with Pythagorean Theorem:

$l=\sqrt{4^2-2^2}=2\sqrt{3}$

4. The base is equal to any face, then both have equal areas. As previously you divide one base into two equal righ triangle to find the slant height, you can calcualte the area of one right triangle and multply it by 2 to calculate B:

$B=2*\frac{bh}{2}=2*\frac{2\sqrt{3}}{2}=2\sqrt{3}$