A company sells a container of mixed nuts that is 50% peanuts and another container that is 80% peanuts. How many cups of each m
ixture would be needed to make 105 cups that is 60% peanuts? Help me to understand how to solve problems like these, please.
1 answer:
<span><span>Let n be the amount of 60% peanuts. Then the amount of 12% peanuts is 12-n. So:
.6n+.12(12-n)=.4(12)
.48n+1.44=4.8
.48n=3.36
n=7 cups 60% peanuts
12-n=5 cups 12% peanuts. ☺☺☺☺ </span><span>
</span></span>
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