The table shows the height of a ball that was dropped from a 380-foot tower. What was the ball's rate of fall during the first 3
2 answers:
<u>Answer:</u>
The correct answer is 60 feet / second.
<u>Step-by-step explanation:</u>
We are given the height of a ball which is falling from a height of 280 feet for 3 seconds.
We are to find the ball's rate of fall during the first 3 seconds.
For that, we will take the difference between the heights and divide it by the time.
Ball's rate = = 60 feet / second
You might be interested in
Answer:
10 units
Step-by-step explanation:
Given that:
Cos a = 3 /5
From trigonometry ;
Cos θ = Adjacent / hypotenus
Side Adjacent angle a = 3 = FD
Hypotenus = 5 = DE
3 / 5 = FD / DE
FD = 6 units
3/5 = 6/DE
DE * 3/5 = 6
DE = 6 ÷ 3/5
DE = 6 * 5 /3
DE = 30 /3
DE = 10 units
