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Greeley [361]
4 years ago
13

The table shows the height of a ball that was dropped from a 380-foot tower. What was the ball's rate of fall during the first 3

seconds?
0s-380ft

1-s-350ft

2s-290ft

3s-200ft
Mathematics
2 answers:
Alex4 years ago
8 0

Answer:

60ft/s

Step-by-step explanation:

To find the rate

rate = f(3) - f(0)

         -------------

         3-0

rate = 200-380

         ---------------

         3-0

rate = -180/3   = -60 ft/s

The negative tells us it is falling

The fall falls 60ft/s

Sever21 [200]4 years ago
4 0

<u>Answer:</u>

The correct answer is 60 feet / second.

<u>Step-by-step explanation:</u>

We are given the height of a ball which is falling from a height of 280 feet for 3 seconds.

We are to find the ball's rate of fall during the first 3 seconds.

For that, we will take the difference between the heights and divide it by the time.

Ball's rate = \frac { 3 8 0 - 2 0 0 } { 3 } = 60 feet / second

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After combining like terms and simplifying 1.17-0.07a+(-3.92a) we get 1.17-3.99a

Step-by-step explanation:

We need to combine like terms to simplify the expression:

1.17-0.07a+(-3.92a)

Like terms: The terms are like when they have same variable and same exponent.

Solving:

1.17-0.07a+(-3.92a)\\=1.17-0.07a-3.92a\\=1.17+(-0.07a-3.92a)\\=1.17+(-3.99a)\\=1.17-3.99a

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Keywords: Solving Expressions

Learn more about Solving Expressions at:

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