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3 years ago

5

Jacob with his mower can mow and trim Mr. Clark's yard in two and a half hours, while Nicole with her mower can mow and trim the

same yard in just two. If they work together and stay out of each other's way, how many minutes will the job take them?

2 answers:

larisa [96]3 years ago

8 0

The maximum pretty sure around an hour.

OLEGan [10]3 years ago

5 0

1 hour 6 minutes 40 seconds

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Find the smallest possible integer m such that 60m is a square number.

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2 years ago

Find the distance between two points. ENTER THE NUMBER THAT GOES BENEATH THE RADICAL SYMBOL.

iVinArrow [24]

<h2>The distance between two points is $\sqrt{98}$ or 9.9 units</h2>

<em><u>Solution:</u></em>

<em><u>The distance between two points is given as:</u></em>

$d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}$

From given,

$(x_1, x_2) = (-5, 5)\\\\(x_2, y_2) = (2, -2)$

<em><u>Substituting the values we get,</u></em>

$d = \sqrt{(2+5)^2+(-2-5)^2}\\\\d = \sqrt{7^2+(-7)^2}\\\\d = \sqrt{49+49}\\\\d = \sqrt{98}\\\\d = 9.899 \approx 9.9$

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3 years ago

8) From a group of 6 men and 6 women, how many committees of 3 men and 4 women<br> can be formed?

Valentin [98]

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3 years ago

What is Xavier’s available lot coverage?

slavikrds [6]

Answer:

<h2> <em><u>720</u></em><em><u>0</u></em></h2>

Step-by-step explanation:

<h3>At first:</h3>

<em><u>G</u></em><em><u>i</u></em><em><u>v</u></em><em><u>e</u></em><em><u>n</u></em><em><u>,</u></em>

Back of lot of the trapezoid = 175

Front of lot of the trapezoid = 185

Length of lot of the trapezoid = 100

<em><u>Therefore</u></em><em><u>,</u></em><em><u> </u></em>

Area of the trapezoid

$= \frac{a + b}{2} c$

<em>[</em><em>On</em><em> </em><em>putting</em><em> </em><em>the</em><em> </em><em>values</em><em>]</em>

$= \frac{175 + 185}{2} \times 100$

<em>[</em><em>On</em><em> </em><em>Simplification</em><em>]</em>

= 360 × 50

<em>[</em><em>On multiplying</em><em>]</em>

= 18000

<em><u>Hence</u></em><em><u>,</u></em>

We got the <em>T</em><em>otal Area </em><em>as</em><em> </em><em>180</em><em>0</em><em>0</em><em>.</em>

<h3>Now:</h3>

<em><u>As</u></em><em><u> </u></em><em><u>per</u></em><em><u> </u></em><em><u>given</u></em><em><u> </u></em><em><u>equation</u></em><em><u>,</u></em>

$\frac{40}{100} = \frac{x}{total \: area}$
To find the value of x

<em><u>Solution</u></em><em><u> </u></em><em><u>,</u></em>

$= > \frac{40}{100} = \frac{x}{total \: area}$

<em>[</em><em>On</em><em> </em><em>putting</em><em> </em><em>Total</em><em> </em><em>Area</em><em> </em><em>=</em><em> </em><em>180</em><em>0</em><em>0</em><em>]</em>

$= > \frac{40}{100} = \frac{x}{18000}$

<em>[</em><em>On</em><em> </em><em>cross</em><em> </em><em>multiplication</em><em>]</em>

=> 40 × 18000 = 100 × x

<em>[</em><em>O</em><em>n</em><em> </em><em>Simplification</em><em> </em><em>]</em>

=> 720000 = 100x

<em>[</em><em>On</em><em> </em><em>dividing</em><em> </em><em>both</em><em> </em><em>sides</em><em> </em><em>with</em><em> </em><em>100</em><em>]</em>

$= > \frac{720000}{100} = \frac{100x}{100}$

<em>[</em><em>On</em><em> </em><em>Simplification</em><em> </em><em>]</em>

=> x = 7200

<em><u>Hence</u></em><em><u>,</u></em>

<em><u>Xavier's</u></em><em><u> </u></em><em><u>avaliable</u></em><em><u> </u></em><em><u>lot</u></em><em><u> </u></em><em><u>coverage</u></em><em><u> </u></em><em><u>(</u></em><em><u>x</u></em><em><u>)</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>720</u></em><em><u>0</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em>

7 0

3 years ago