Question

Which equation when graphed has a maximum value at x = −2? A) y = −x2 − 20x − 16, B) y = −x2 − 16x − 12, C) y = −4x2 − 20x − 16, D) y = −4x2 − 16x − 12

Answer 1

Answer:

Option D. $y=-4x^{2} -16x-12$

Step-by-step explanation:

using a graphing tool

Graph and determine the vertex in each case

we know that

If the equation has a maximum value at x=-2, then the x-coordinate of the vertex must be  equal to -2 and the parabola open downward

case A) $y=-x^{2} -20x-16$

The vertex is the point $(-10,84)$

case B) $y=-x^{2} -16x-12$

The vertex is the point $(-8,52)$

case C) $y=-4x^{2} -20x-16$

The vertex is the point $(-2.5,9)$

case D) $y=-4x^{2} -16x-12$

The vertex is the point $(-2,4)$ -------> is the answer

see the attached figure