Answer:
2c^2 - 2c - 3
Step-by-step explanation:
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Group together the 'c' terms in 2 + 7c – 4c2 – 3c + 4:
2 + 4c and -4c^2 + 4 Then we have:
-4c^2 + 4c + 6
We should reduce this by factoring -2 out of all three terms:
2c^2 - 2c - 3 This is the desired quadratic in standard form.
A is definitely the answer.
Answer:
Number is yellow box=3
Step-by-step explanation:
We know this because the way we get that number is subtracting the two numbers above it, which is 8 and 5, which give us 3.
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The answers to the questions are
- The mathematical model is given as s = −16t2 + 1054
- The height after 4.5 seconds is 730 feet
- the time it would take to strike the ground is 8.11 seconds.
<h3>How to solve for the position of the object</h3>
The mathematical model of this problem would be written as
s = −16t2 + v0t + s0
s0 = 1054
then we would have
s = −16t2 + 1054
b. after 4.5 seconds the height is going to be
s = −16t2 + 1054
= −16(4.5)² + 1054
= -16 * 20.25 + 1054
= 730
C. the time that it takes to strike the ground
s = −16t² + 1054
= 16t² = 1054
t² = 1054/16
= 65.88
t = √65.88
t = 8.11
Hence the time it would take to strike the ground is 8.11 seconds.
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(3x-4y)^2=9x^2-24x+16y^2
(3x-2)(9x^2+6x+4)=27x^3-8
